The molar mass of the unknown gas is 184.96 g/mol
<h3>Graham's law of diffusion </h3>
This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e
R ∝ 1/ √M
R₁/R₂ = √(M₂/M₁)
<h3>How to determine the molar mass of the unknown gas </h3>
The following data were obtained from the question:
- Rate of unknown gas (R₁) = R
- Rate of CH₄ (R₂) = 3.4R
- Molar mass of CH₄ (M₂) = 16 g/mol
- Molar mass of unknown gas (M₁) =?
The molar mass of the unknown gas can be obtained as follow:
R₁/R₂ = √(M₂/M₁)
R / 3.4R = √(16 / M₁)
1 / 3.4 = √(16 / M₁)
Square both side
(1 / 3.4)² = 16 / M₁
Cross multiply
(1 / 3.4)² × M₁ = 16
Divide both side by (1 / 3.4)²
M₁ = 16 / (1 / 3.4)²
M₁ = 184.96 g/mol
Learn more about Graham's law of diffusion:
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Answer:
Formaldehyde(CHO) or methanal is your answer.
25 m/s I believe because you are looking for t and if you changed the formula to t=s(d) or just keep the formula how it is and multiply to cancel out d you would be left with 5(5) so 25m/s
Answer:
76%
Explanation:
The lab grade of the student is made of report sheets, lab exams and lab quizzes with different weights for each score. To find the lab grade we need to multiply each score with respective weight. He has 86% in the report sheet which has 35% weight, 66% in the lab exam which have 35% weight, and 76% in the quizzes which have 30% weight. The score will be:
86%*35% + 66%*35% + 76%*30%= 76%
His score for the lab grade will be 76%