Question

An automobile tire contains air at 320.×103 Pa at 20.0 ◦C. The stem valve is removed and the air is allowed to expand adiabatically against the constant external pressure of 100.×103 Pa until P = Pexternal. Assume the air is an ideal gas with C¯ V = 5/2 R (diatomic). Calculate the final temperature.

Answer 1

Answer:

6.15.3 k

Explanation:

From the question we can see that

q = 0,  Δu = w

Then,

$T_f = \frac{C_{V,m}+RP_{ext}P_i}{C_{V,m}+RP_{ext}P_f} T_i$

putting values wet

=$\frac{2.5\times 8.314+8.314\left(10^5\right)\left(3.20\times 10^5\right)}{2.5\times 8.314+\left(8.314\right)\left(10^5\right)\left(10^5\right)}\times \:293$

T_f = 615.3 K