Answer:
96 g of O
Explanation:
Mg(OH)₂ → Magnesium hydroxide
Molar mass → 24.3g/mol . 1 + 16g/mol . 2 + 1g/mol . 2 = 58.3 g/mol
We determine the moles of hydroxide → 175 g . 1mol/58.3g = 3 moles
Let's make some rule of three:
In 100 g of compound we have 54.87 g of O
In 58.3 g of compound we may have (58.3 . 54.87) / 100 = 32 g
So, 1 mol of hydroxide has 32 g of oxygen
3 moles of hyroxide may have (3 .32)/1 = 96 g of O
Answer:
There are 0.0267 moles of oxygen in 0.658 grams of magnesium nitrate.
Explanation:
Mass of magnesium nitrate = m = 0.658 g
Molar mass of magnesium nitrate = M = 148 g/mol
Moles of magnesium nitrate = n

1 mole of magnesium nitrate has 6 moles of oxygen atoms. Then 0.004446 moles magnesium nitrate will have :

There are 0.0267 moles of oxygen in 0.658 grams of magnesium nitrate.
<span>Answer:
Boyle began to detach chemistry from the mysticism of alchemy. He declared that most followers of alchemy were not interested in the fundamental causes of phenomena and instead looked to.</span>