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3 years ago

BRAINLIEST & 25 POINTS PLEASE HELP URGENT DUE IN 10 MINUTES.

Mathematics

1 answer:

Cerrena [4.2K]3 years ago

5 0

Answer:

C) 24 adults

Step-by-step explanation:

Let A be the number of adults and C be the number of children.

If a ticket costs $8 per adult, we can express this as 8A

If a ticket costs $5 per child, we can express this as 5C

Combining the two expressions, we can write 8A+5C=272 as our first equation since the total amount of money collected is $272.

Our second equation would be A+C=40 since there are 40 people.

Now, we can take the second equation and write it as C=40-A so we can substitute the value of C into the first equation as 40-A so we only have to deal with one variable, the amount of adults that went to the theater.

The first equation now becomes 8A+5(40-A)=272 and is much easier to solve:

8A+5(40-A)=272

8A+200-5A=272

3A+200=272

3A=72

A=24

Therefore, there are 24 adults

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Step-by-step explanation:

Information given

$\bar X=147.3$ represent the sample mean for the amount of time spent at part time jobs

$s=50$ represent the sample standard deviation

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$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value for the test

System of hypothesis

We want to analyze if the true mean for the amount of time spent at part time jobs is higher than 120, the system of hypothesis would be:

Null hypothesis: $\mu \leq 120$

Alternative hypothesis: $\mu > 120$

Since we don't know the population deviation the statistic is given by:

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Replacing the info given we got:

$t=\frac{147.3-120}{\frac{50}{\sqrt{15}}}=2.115$

Now we can calculate the degrees of freedom

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If we find a critical value in the t distribution with 14 degrees of freedom who accumulates 0.05 of the area in the right we got $t_{critc}= 1.761$

Since the calculated value is higher than the critical value we have enough evidence to conclude that the true mean is significantly higher than 120 minutes for the average time of part time jobs

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