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RoseWind [281]
3 years ago
11

A few hundred tons of comet dust are added to Earth daily from the millions of meteors that enter our atmosphere. Estimate the t

ime it would take for Earth to get 0.1% heavier at this rate. is this mass accumulation significant for earth as a planet? Explain.
Physics
1 answer:
slavikrds [6]3 years ago
7 0

Answer:

=9.953\times 10^{16} Days

Explanation:

The weight of the Earth = 5.972\times 10^{24} KG

0.1% of the weight of the Earth will be

=5.972\times 10^{24} \times \frac{1}{1000}

=5.972\times 10^{21} KG

As per a research conducted in 2014, it was estimated that 60 tons of cosmic dust fall on the Earth every day. So, the time it would take for the cosmic dust to make up 0.1% of the weight of the Earth will be,

=\frac{1}{60000}\times 5.972\times 10^{21} Days

=9.953\times 10^{16} Days.

Though the quantity of the cosmic dust might seem huge but its negligible in comparison to the weight of the Earth. Also, this cosmic dust plays a role in formation of clouds and fertilization of plankton in Polar region.

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The following objects have velocity and mass as given: Object A: m=5 kg, ⃗v=−11 ^j Object B: m=6 kg, ⃗v=5^ i +8.7 ^ j Object C:
Fofino [41]

Answer:

For object A

m = 5 kg ,   v= -11 j

For B object

m = 6 kg  ,  v= 5 i +8.7 j

For object C

m = 10 kg   ,   v= -10 i

We know that

Linear momentum   P= m v   kg.m/s

a) A and C

Momentum in y direction

Py=- 5 x 11 j= - 55 j  kg.m/s

Momentum in x direction

Px=- 10 x 10 j= - 100 i    kg.m/s

b) B and C

Momentum in y direction

Py=6 x 8.7 j= 52.2 j    kg.m/s

Momentum in x direction

Px=( 6 x 5 - 10 x 10 ) i = - 70 i   kg.m/s

c) A ,B and C

By using data of a and b

Momentum in y direction

Py= 6 x 8.7 - 5 x 11 j= -2.8 j    kg.m/s

Momentum in x direction

Px=  6 x 5 -10 x 10 i = -70 i   kg.m/s

4 0
3 years ago
The strength of the Earth’s magnetic field B at the equator is approximately equal to 5 × 10−5 T. The force on a charge q moving
Blizzard [7]

Answer:

2.4\cdot 10^{-11} N

Explanation:

Since the Earth's magnetic field is perpendicular to your direction of motion, the strength of the magnetic force exerted on your head is given by:

F=qvB

where:

q=6\cdot 10^{-9}C is the charge on your head

v=80 m/s is the speed at which you are moving

B=5\cdot 10^{-5} T is the strength of the magnetic field of the Earth

By substituting these numbers into the equation, we find the strength of the magnetic force:

F=(6\cdot 10^{-9}C)(80 m/s)(5\cdot 10^{-5} T)=2.4\cdot 10^{-11} N

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B)False........... It's efficiency factor
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Answer:

Explanation:

I can give you four for certain.

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Silver

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7 0
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