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RoseWind [281]
3 years ago
11

A few hundred tons of comet dust are added to Earth daily from the millions of meteors that enter our atmosphere. Estimate the t

ime it would take for Earth to get 0.1% heavier at this rate. is this mass accumulation significant for earth as a planet? Explain.
Physics
1 answer:
slavikrds [6]3 years ago
7 0

Answer:

=9.953\times 10^{16} Days

Explanation:

The weight of the Earth = 5.972\times 10^{24} KG

0.1% of the weight of the Earth will be

=5.972\times 10^{24} \times \frac{1}{1000}

=5.972\times 10^{21} KG

As per a research conducted in 2014, it was estimated that 60 tons of cosmic dust fall on the Earth every day. So, the time it would take for the cosmic dust to make up 0.1% of the weight of the Earth will be,

=\frac{1}{60000}\times 5.972\times 10^{21} Days

=9.953\times 10^{16} Days.

Though the quantity of the cosmic dust might seem huge but its negligible in comparison to the weight of the Earth. Also, this cosmic dust plays a role in formation of clouds and fertilization of plankton in Polar region.

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Rumus mencari masa jenis​
Black_prince [1.1K]

what?????????????!!!!!!!!!!!!!!

6 0
3 years ago
Read 2 more answers
A sample of metallic frewium weighs 185N on a spring scale in air. When immersed in pure water, the frewium pulls on the scale w
balu736 [363]

Wow !  This one could have some twists and turns in it.
Fasten your seat belt.  It's going to be a boompy ride.

-- The buoyant force is precisely the missing <em>30N</em> .

--  In order to calculate the density of the frewium sample, we need to know
its mass and its volume.  Then, density = mass/volume .

-- From the weight of the sample in air, we can closely calculate its mass.

   Weight = (mass) x (gravity)
   185N = (mass) x (9.81 m/s²)
   Mass = (185N) / (9.81 m/s²) = <u>18.858 kilograms of frewium</u> 

-- For its volume, we need to calculate the volume of the displaced water.

The buoyant force is equal to the weight of displaced water, and the
density of water is about 1 gram per cm³.  So the volume of the
displaced water (in cm³) is the same as the number of grams in it.

The weight of the displaced water is 30N, and weight = (mass) (gravity).

           30N = (mass of the displaced water) x (9.81 m/s²)

           Mass = (30N) / (9.81 m/s²) = 3.058 kilograms

           Volume of displaced water = <u>3,058 cm³</u>

Finally, density of the frewium sample = (mass)/(volume)

      Density = (18,858 grams) / (3,058 cm³) = <em>6.167 gm/cm³</em> (rounded)

================================================

I'm thinking that this must  be the hard way to do it,
because I noticed that

       (weight in air) / (buoyant force) =  185N / 30N = <u>6.1666...</u>

So apparently . . .

        (density of a sample) / (density of water) =

                                  (weight of the sample in air) / (buoyant force in water) .

I never knew that, but it's a good factoid to keep in my tool-box.


3 0
3 years ago
[O.04H]The table below shows the use of some energy production methods over time.
mr Goodwill [35]

I think The coastal areas were highly polluted

8 0
3 years ago
Read 2 more answers
What kind of symmetry do you have
Keith_Richards [23]
During the daytime, I have mostly line symmetry.

During the night, I often have almost spherical symmetry.
5 0
3 years ago
Read 2 more answers
A jogger moves from a position x =
vlada-n [284]

Answer:

3 m/s

Explanation:

We'll begin by calculating the change in displacement of the jogger. This can be obtained as follow:

Initial displacement (d₁) = 4 m

Final displacement (d₂) = 16 m

Change in displacement (Δd) =?

Δd = d₂ – d₁

Δd = 16 – 4

Δd = 12 m

Finally, we shall determine the determine the average velocity. This can be obtained as follow:

Change in displacement (Δd) = 12 m

Time (t) = 4 s

Velocity (v) =?

v = Δd / t

v = 12 / 4

v = 3 m/s

Thus, the average velocity of the jogger is 3 m/s

5 0
3 years ago
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