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nataly862011 [7]

4 years ago

7

Which of the following forms of light can be observed with telescopes at sea level?Select all that apply.Select all that apply.X

raysultraviolet lightvisible lightinfrared lightradio waves

1 answer:

Semenov [28]4 years ago

5 0

rays ultraviolet light visible light infrared light radio waves

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ludmilkaskok [199]

Answer: W represents an element Y represents a mixture

Explanation: I just took a quiz on this and got it right. Good Luck

4 0

3 years ago

An unmarked police car traveling a constant 85 km/h is passed by a speeder. Precisely 2.00 s after the speeder passes, the polic

steposvetlana [31]

Answer:

observe o gráfico abaixo que mostra o número de internação em um hospital no município no período de 1960

6 0

3 years ago

a quarterback throws a football with angle of elevation 40degrees and speed 60ft/s. Find the horizontal and vertical components

pshichka [43]

<span>
the horizontal velocity would be equal to
Vh = sin (40) /60
= 0.74 * 60
= 44
</span>
the Vertical velocity would be equal to
<span>Vv = cos(40) * 60
=40</span>

4 0

3 years ago

A mass is attached to an ideal spring. At time t = 0 the spring is at its natural length and the mass is given an initial veloci

JulijaS [17]

Answer:

t = T/4

Explanation:

The power delivered to the mass by the spring is work done by the spring per second.

$P = \frac{dW}{dt}$

The work done by the spring is equal to the elastic potential energy stored in the spring.

$U = \frac{1}{2}kx^2$

The maximum energy stored in the spring is at the amplitude of the oscillation.

$U_{max} =\frac{1}{2}kA^2$

So the first time the mass reaches to its amplitude can be found by the following equation of motion:

$x = A\cos(\omega t + \phi)\\\phi = \pi/2 ~because ~at ~t= 0, ~ x = 0\\0 = A\cos(0 + \pi/2)\\x = A\cos(\omega t + \pi/2)$

When the mass reaches the amplitude:

$A = A\cos(\omega t + \pi/2)\\1 = \cos(\omega t + \pi/2)\\\omega t + \pi/2 = \pi$

because cos(π) = 1.

$\omega t = \pi/2$

Using ω = 2π/T,

$\omega t = \pi/2\\\frac{2\pi}{T}t = \pi/2\\t = \frac{T}{4}$

4 0

4 years ago

You buy a plastic dart gun, and being a clever physics student you decide to do a quick calculation to find its maximum horizont

Rasek [7]

The time of flight of the dart is 36.761 s, it can be used to solve the initial velocity of the dart bt the formula t= 2v/g, which v is equal to 180.31 m/s which is actually very fast. We can now solve the maximum distanc H= v^2/2g which is equal to 1657.11 m.

5 0

3 years ago