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tia_tia [17]
3 years ago
10

I'm not even sure if this is the right category but here we go. All my points and brainliest. I'm counting on you guys.

Physics
1 answer:
zlopas [31]3 years ago
7 0

Answer:

When a substance is heated, it gains thermal energy. Therefore, its particles move faster and its temperature rises. When a substance is cooled, it loses thermal energy, which causes its particles to move more slowly and its temperature to drop.

Explanation:

Brainliest???

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A ball is dropped from a height h and falls the last half of its distance in 4 seconds. How long does the ball fall? From what h
dlinn [17]

Answer:

How long does the ball fall is t_2 =  13.66 (s).

From what height is the ball originally dropped is h=  913.90 (m).

Explanation:

8 0
3 years ago
3. A car going 22m/s accelerates to pass a truck. Five seconds late the car is going 35m/s. Calculate the acceleration of the ca
DedPeter [7]

Answer:

57

Explanation:

6 0
2 years ago
A meter stick A hurtles through space at a speed v = 0.25c relative to you, with its length aligned with the direction of motion
yaroslaw [1]

Answer:

L_0\approx1.0328\ m

Explanation:

Given:

  • relativistic length of stick A, L=1\ m
  • relativistic velocity of stick A with respect to observer, v=0.25c=7.5\times 10^{7}\ m.s^{-1}

<em>Since the object is moving with a velocity comparable to the velocity of light  with respect to the observer therefore the length will appear shorter according to the theory of relativity.</em>

<u> Mathematical expression of the theory of relativity for length contraction:</u>

L=\frac{L_0}{\gamma}

where:

L = relativistic length

L_0= original length at rest

\gamma = Lorentz factor =\frac{1}{\sqrt{1-\frac{v^2}{c^2} } }

\Rightarrow 1=\frac{L_0}{\frac{1}{\sqrt{1-\frac{(0.25c)^2}{c^2} } }}

L_0=\frac{1}{\sqrt{1-\frac{(0.25c)^2}{c^2} } }

L_0\approx1.0328\ m

4 0
3 years ago
As you slide a heavy box across the floor, friction applies a force of -100 N
nirvana33 [79]

Answer:

A -500J

Explanation:

because W=Fs

100 × 5 = 500

4 0
3 years ago
Read 2 more answers
Two flat 4.0 cm × 4.0 cm electrodes carrying equal but opposite charges are spaced 2.0 mm apart with their midpoints opposite ea
serious [3.7K]

Answer:

1.77 x 10^-8 C

Explanation:

Let the surface charge density of each of the plate is σ.

A = 4 x 4 = 16 cm^2 = 16 x 10^-4 m^2

d = 2 mm

E = 2.5 x 10^6 N/C

ε0 = 8.85 × 10-12 C2/N ∙ m2

Electric filed between the plates (two oppositively charged)

E = σ / ε0

σ = ε0 x E

σ = 8.85 x 10^-12 x 2.5 x 10^6 = 22.125 x 10^-6 C/m^2

The surface charge density of each plate is ± σ / 2

So, the surface charge density on each = ± 22.125 x 10^-6 / 2

                                                                 = ± 11.0625 x 10^-6 C/m^2  

Charge on each plate = Surface charge density on each plate x area of each plate

Charge on each plate = ± 11.0625 x 10^-6  x 16 x 10^-4 = ± 1.77 x 10^-8 C

7 0
3 years ago
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