Question

Suppose S and T are mutually exclusive events find P(S or T) if P(S)=1/3 and P(T)=5/12

Answer 1

Answer:

The value of P(S or T) is 3/4.

Step-by-step explanation:

It is given that S and T are mutually exclusive events. It means intersection of S and T is 0.

$S\cap T=0$

$P(S\cap T)=0$

We need to find the value of  P(S or T). It means we have to find the probability of union of S and T.

$P(S\cup T)=P(S)+P(T)-P(S\cap T)$

Substitute the given values in the above formula.

$P(S\cup T)=\frac{1}{3}+\frac{5}{12}-(0)$

$P(S\cup T)=\frac{4+5}{12}$

$P(S\cup T)=\frac{9}{12}$

$P(S\cup T)=\frac{3}{4}$

Therefore the value of P(S or T) is 3/4.

Answer 2

Answer:

P(S or T)= 3/4

Step-by-step explanation:

Given:

S and T are mutually exclusive events

find P(S or T)

P(S or T)= P(S) + P(T)

             = 1/3 +5/12

             =4+5/12

              =9/12

               =3/4 !