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WITCHER [35]
3 years ago
5

Quadrilateral ABCD quadrilateral WXYZ. If AD = 12, DC = 6, and ZY = 36, find WZ.

Mathematics
2 answers:
valentinak56 [21]3 years ago
8 0
If they're similar it would be 72, 36x2=72.
mihalych1998 [28]3 years ago
7 0

Answer: C. 72

Step-by-step explanation:

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How to know if a function is periodic without graphing it ?
zhenek [66]
A function f(t) is periodic if there is some constant k such that f(t+k)=f(k) for all t in the domain of f(t). Then k is the "period" of f(t).

Example:

If f(x)=\sin x, then we have \sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x, and so \sin x is periodic with period 2\pi.

It gets a bit more complicated for a function like yours. We're looking for k such that

\pi\sin\left(\dfrac\pi2(t+k)\right)+1.8\cos\left(\dfrac{7\pi}5(t+k)\right)=\pi\sin\dfrac{\pi t}2+1.8\cos\dfrac{7\pi t}5

Expanding on the left, you have

\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2

and

1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5

It follows that the following must be satisfied:

\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}

The first two equations are satisfied whenever k\in\{0,\pm4,\pm8,\ldots\}, or more generally, when k=4n and n\in\mathbb Z (i.e. any multiple of 4).

The second two are satisfied whenever k\in\left\{0,\pm\dfrac{10}7,\pm\dfrac{20}7,\ldots\right\}, and more generally when k=\dfrac{10n}7 with n\in\mathbb Z (any multiple of 10/7).

It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when k is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2

\cos\left(\dfrac{7\pi}5(t+20)\right)=\cos\dfrac{7\pi t}5\underbrace{\cos28\pi}_1-\sin\dfrac{7\pi t}5\underbrace{\sin28\pi}_0=\cos\dfrac{7\pi t}5

More generally, it can be shown that

f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))

is periodic with period \mbox{lcm}(b_1,\ldots,b_n,d_1,\ldots,d_n).
4 0
2 years ago
What is the mean median and mode of 5.6 6.8 1.2 6.5 7.9 6.5 ???
rjkz [21]
Median - 6.5
mode- 6.5
mean-5.8
8 0
2 years ago
Mario says that the expression 4+3n² has four terms: 4, 3, n, and 2. Is he correct? explain.
stich3 [128]

Mario says that the expression 4+3n^2 has four terms: 4, 3, n, and 2. Mario is incorrect

<em><u>Solution:</u></em>

Given that the expression is:

4+3n^2

Given that, Mario says that the above expression has four terms

But Mraio is incorrect

Because the given expression has two terms only

4 is one of the term

3n^2 is another term

So there are totally 2 terms only

A term can be a signed number, a variable, or a constant multiplied by a variable or variables

Here 3 is a constant multiplied by n^2

So, 3n^2 is one term

Each term in an algebraic expression is separated by a + sign or - sign

Thus there are two terms in mario expression

8 0
2 years ago
What is (4c)^2d ?<br> c = 5 and d = 8
Arte-miy333 [17]

Answer:

  3200

Step-by-step explanation:

Replace the variables with their values and do the arithmetic.

  (4·5)²·8 = 20²·8 = 400·8 = 3200

6 0
3 years ago
PLEASE, I NEED HELP FOR A CLASS. The length of triangle base is 26. A line, which is parallel to the base divides the triangle i
sasho [114]

Answer:

DE=18.38

Step-by-step explanation:

It is given that the length of triangle base is 26 that is BC=26.

A line, which is parallel to the base divides the triangle into two equal area parts.

Therefore, from the given information, \frac{{\triangle}ADE}{ar ABC}=\frac{1}{2}.

Now, since it is given that A line, which is parallel to the base divides the triangle into two equal area parts, thus

\frac{ar ADE}{arABC}=\frac{1}{2}=\frac{(DE)^{2}}{(BC)^{2}}

⇒\frac{(DE)^{2}}{(BC)^{2}}=\frac{1}{2}

⇒\frac{(DE)^{2}}{(26)^{2}}=\frac{1}{2}

⇒(DE)^{2}=13{\times}26=338

⇒DE=18.38

7 0
3 years ago
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