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Serggg [28]
2 years ago
5

Please help I am brianab9968 If u r there babe

Mathematics
1 answer:
12345 [234]2 years ago
3 0

Answer:

After simplifying ur ans comes out to be option a

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The vertices of xyz are x(-3,-6), Y(21,-6), and z(21,4). What is the perimeter of the triangle
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Note that this a right-angled triangle with the right angle at Y. 

<span>Use coordinates of the point to find XY and YZ </span>

<span>XY = 21 - (-3) </span>

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<span>YZ = 4 - (-6) </span>

<span>= 10 </span>

<span>Use Pythagoras theorem to XZ </span>

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The perimeter of a triangle is 47 feet. One side of the triangle is one foot longer than the second side. The third side is four
Ugo [173]

Answer:

The lengths of all three sides (in feet) are = 15, 14, and 18 feet

Step-by-step explanation:

Perimeter of Triangle = 47ft

Let the one side be 'x'

<em>Side 1 = x</em>

One side of the triangle is one foot longer than the second side

<em>Side 2 = x - 1</em>

<em>The third side is four feet longer than the second side</em>

<em>Side 3 = (x - 1) + 4</em>

<em />

<em>Perimeter = sum of all sides</em>

<em>47 = x + (x - 1) + (x - 1) + 4</em>

<em>47 = x + x - 1 + x - 1 + 4</em>

<em>47 = 3x + 2</em>

<em>47 - 2 = 3x</em>

45 = 3x

<u>x = 15</u>

substitute for x in each of the sides

<em>Side 1 = x                   => </em><em>15 feet</em>

<em>Side 2 = x - 1              => 15 - 1 = </em><em>14 feet</em>

<em>Side 3 = (x - 1) + 4      => 14 + 4 = </em><em>18 feet</em>

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