Answer:
As follows, (shortened)
Step-by-step explanation:
1.AB=CD (Given)
2.AB+BC=CD+BC ( By additive property, adding BC to both sides)
3.AB+BC=CD+DE (Given, BC=DE, By substitution property replacing BC by DE)
4.AC=CE(By segment addition, and substitution property)
<h3>Option D) Seagull, crow | bat, mosquito</h3>
Step-by-step explanation:
10-5 2/3
=10-3.333
=6.667 ANS...
<h3>
The combined weight of a car and truck is given as the polynomial P(W) = x³ + x² + 11 x + 300</h3>
Step-by-step explanation:
The weight of the car is given as:
P(C) = x² + 10 x + 200
The weight of the truck is given as:
P(T) = x³ + x + 100
Now, the combined weight of both vehicles is given as
= Weight of Car P(C) + Weight of Truck P(T)
P(W) = x² + 10 x + 200 + x³ + x + 100
= x³ + x² + (10 x + x)+ (200 + 100)
= x³ + x² + 11 x + 300
⇒ The combined weight of a car and truck is given as the polynomial P(W) = x³ + x² + 11 x + 300
Answer:
1333.333 miles
Step-by-step explanation:
Let x = distance covered in 1 day.
Given the following data;
Distance = 800 miles
Time = 3 days
<em>In 1 day he would cover;</em>
1 day = x miles
3 day = 800 miles
800 = 3x
x = 800/3
x = 266. 667
In 5 days;
5x = 5 * 266.667 = 1333.333 miles
Or
Let x = distance in 5 days.
Distance in miles = time in days
800 miles = 3 days
x miles = 5 days
Cross multiplying, we have;
3x = 800 * 5
x = 4000/3
x = 1333.333 miles
<em>Therefore, in 5 days Ken would drive 1333.333 miles. </em>