They are determined by the length of time it takes for light to travel from the Earth to the desired star
According to Le cha telier's principle when we increase the pressure of a equilibrium reaction the reaction shift to the side where few moles of gas present.
Your reaction (Notice - I guess the reaction you written is wrong, but still I'm solving with your given prediction)
3NaI (g) + H2 (g) = 2NaHI (g)
Where access of sodium iodide is reacting with Hydrogen gas to form NaHI molecule.
Number of moles of gas on reaction side - 3+2 = 5 moles
Number of moles of gas on product side - 2 moles
<em>Conclusion- the reaction will shift to the right of the reaction</em>
Answer:
1)KNO3 ( pottasium trioxonitrate (V)
2)Ca(NO3)2 (calcium trioxonitrate (V
Explanation:
1)KNO3 ( pottasium trioxonitrate (V)
2)Ca(NO3)2 (calcium trioxonitrate (V)
Thses two compounds are metallic compounds and does not react with either the acid or the base.
Write the type of metal, based on your examination of the periodic table?
1)KNO3 ( pottasium trioxonitrate (V) have a potassium element which belongs to group 2 of the Periodic table which is an alkaline metal and can react with water or steàm
2)Ca(NO3)2 (calcium trioxonitrate (V) has calcium metal element which is an alkaline earth metal in the Periodic table and they react with Hallogens
Answer:- Oxidation number of Cl does not change as it is -1 on both sides.
Explanations:- oxidation number of Mg on reactant side is 0 as it is in its elemental form(not combined with another element).
Oxidation number of hydrogen in its compounds is +1, so if H is +1 in HCl the oxidation number of Cl is -1 as the sum has to be zero.
On product side, Mg oxidation number is +2 as the oxidation number of alkaline earth metals in their compounds is +2.
Two Cl are present in magnesium chloride, so if Mg is +2 then Cl is -1.
Oxidation number of H on product side is 0 as it is present in its elemental for, 
,
So, it is only chlorine(Cl) whose oxidation number does not change for the given equation.
