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Sedaia [141]
2 years ago
15

Please help This is for my chemistry class and I need to get it done but I’m lost and need answers

Chemistry
1 answer:
Vanyuwa [196]2 years ago
5 0

Answer:

chlorine is a non metal.

sodium is a alkali metal.

helium is a noble gas.

nickel is a transition metal

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Try Plants maybe??????
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2 years ago
How many moles are contained in 2.3 liters of a 1.2M solution?
elena-s [515]

Answer:

\boxed {\boxed {\sf 2.76 \ mol}}

Explanation:

Molarity is found by dividing the moles of solute by liters of solution.

molarity = \frac {moles}{liters}

We know the molarity is 1.2 M (mol\liter) and there are 2.3 liters of solution. Substitute the known values into the formula.

1.2 \ mol/liter= \frac {x}{2.3 \ liters}

Since we are solving for x, we must isolate the variable. It is being divided by 2.3 and the inverse of division is multiplication. Multiply both sides by 2.3 liters.

2.3 \ liters *1.2 \ mol/liter= \frac {x}{2.3 \ liters}* 2.3 \ liters\\2.3 *1.2 \ mol= x\\2.76 \ mol =x

In a solution with a molarity of 1.2 and 2.3 liters of solution, there are 2.76 moles.

3 0
3 years ago
The movement of food energy from one organism to another is called a
Leni [432]
It’s called a food chain
6 0
3 years ago
A student uses a solution of 1.2 molar sodium hydroxide (NaOH) to calculate the concentration of a solution of sulfuric acid (H2
Mila [183]

From the calculations, the concentration of the acid is 0.24 M.

<h3>What is neutralization?</h3>

The term neutralization has to do with a reaction in which an acid and a base react to form salt and water only.

We have to use the formula;

CAVA/CBVB = NA/NB

CAVANB =CBVBNA

The equation of the reaction is; 2NaOH + H2SO4 ----> Na2SO4 + 2H2O

CA = ?

CB = 1.2 M

VA =  50 mL

VB = 20 mL

NA = 1

NB = 2

CA = CBVBNA/VANB

CA = 1.2 M * 20 mL * 1/ 50 mL * 2

CA = 0.24 M

Learn more about neutralization:brainly.com/question/27891712

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5 0
1 year ago
Describe a method to calculate the average atomic mass of the sample in the previous question using only the atomic masses of li
alexira [117]

Answer:

Explanation:

To calculate their average atomic masses which is otherwise known as the relative atomic mass, we simply multiply the given abundances of the atoms and the given atomic masses.

The abundace is the proportion or percentage or fraction by which each of the isotopes of an element occurs in nature.

This can be expressed below:

        RAM = Σmₙαₙ

where mₙ is the mass of isotope n

           αₙ is the abundance of isotope n

for this problem:

RAM of Li = m₆α₆ + m₇α₇

       m₆ is mass of isotope Li-6

        α₆ is the abundance of isotope Li-6

       m₇ is mass of isotope Li-7

        α₇ is the abundance of isotope Li-7

3 0
3 years ago
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