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Artist 52 [7]
2 years ago
8

What mass of barium sulfate (233 g/mol) is produced when 125 mL of a 0.150 M solution of barium chloride is mixed with 125 mL of

a 0.150 M solution of iron(III) sulfate
Chemistry
1 answer:
Rzqust [24]2 years ago
4 0

Answer:

4.37 g of barium sulphate

Explanation:

The reaction equation is;

3BaCl2(aq) + Fe2(SO4)3(aq) ---->3 BaSO4(s) + 2FeCl3(aq)

From the question, the number of moles of both barium chloride and FeSO4 = 125/1000 L × 0.150 M = 0.01875 moles

To find the limiting reactant;

3 moles of barium chloride yields 3 moles of barium sulphate

0.01875 moles of barium chloride yields 3 × 0.01875 moles/3 = 0.01875 moles of barium sulphate

1 mole of iron III sulphate yields 3 moles of barium sulphate

0.01875 molesof iron III sulphate yields 0.01875 moles ×3/1 = 0.05625 moles of barium sulphate

Hence,barium chloride is the limiting reactant

Amount of barium sulphate produced = 0.01875 moles × 233 g/mol = 4.37 g of barium sulphate

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The half-life of C-14 is 5470 years. If a particular archaeological sample has one-quarter of its original radioactivity remaini
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Answer:

When there remains one-quarter of the sample, the age of the sample is 10940 years

Explanation:

<u>Step 1:</u> Data given

The half-life of C-14 is 5470 years.

The half- life time is the time required for a quantity to reduce to half of its initial value.

This means after 5470 years there remains half of the C-14 sample.

To remain a quarter of the sample, another cycle of 5470 years is required.

This means 2 half-lives should have passed to remain a quarter of the sample.

<u>Step 2</u>: Calculate it's age

t/(t/1/2) = 2

⇒ with t = the age (or time) of the sample

⇒ with t(1/2) = the half-life time of the sample = 5470 years

⇒ with 2 = the number of halvf- lives passed

t/5470 = 2

t = 2*5470 = 10940 years

When there remains one-quarter of the sample, the age of the sample is 10940 years

3 0
2 years ago
The detonation of some amount of TNT causes the volume of nearby gas to increase from 10.0 L to 90.0 L (the pressure remains con
Gnom [1K]

Internal combustion energy for TNT(Trinitro toluene) is found to be  -170 kJ.

Internal energy= (- heat evolved by the system) + Work done by the system

ΔU = -Q+W

W = - PΔV

P= pressure

ΔV =difference in volume

Given,

V1 = 10 L

V2 = 90 L

∴ΔV = V2-V1 = 90-10 = 80 L

P = 1 atm

∴W = - ( 1× 80)

      = -80 kJ

Heat evolved by the system = 90 kJ

∴Δ U= - 90 kJ - 80 kJ

       = - 170 kJ

Thus, Internal combustion energy for TNT(Trinitro toluene) is found to be -170 kJ.

NOTE : here work done by the system is considered negative and also heat evolved by the system is taken -Ve.

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brainly.com/question/1370118

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6 0
1 year ago
Calculate the density of oxygen,
abruzzese [7]

Answer:

density of oxygen = 1.307 g/l

Explanation:

given pressure = 1 atm temperature = 298 k

PM=DRT

where p is pressure M is molecular mass D is density R is gas constant and T is temperature

substituting the values in the equation

1\times 32=D\times 0.0821\times 298

D = 1.307 g/l.

5 0
3 years ago
What's the chemical reaction of Grignard in Organic Chemistry?​
Paul [167]

Answer:

Grignard reagents are formed by the reaction of magnesium metal with alkyl or alkenyl halides. They're extremely good nucleophiles, reacting with electrophiles such as carbonyl compounds

Explanation:

hope this helps!

8 0
3 years ago
1.The splitting of a heavy, unstable nucleus into two lighter nuclei is called _____.
fredd [130]

Answer:

A) Fission

Explanation:

Fission is the splitting of a heavy, unstable nucleus into two lighter nuclei, and fusion is the process where two light nuclei combine together releasing vast amounts of energy.

6 0
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