Answer:
P (H₂) = 741 torr
Explanation:
Let's begin by listing out the given parameters:
Temperature (water) = 298 K, volume = 45.6 mL,
atmospheric pressure, P (total) = 765 torr, vapor pressure of water, P (H₂O) = 24 torr
To get the pressure of inside the tube, P (H₂), we apply Dalton's Law of Partial Pressure and we have:
P (total) = P (H₂) + P (H₂O)
P (total) = 765 torr, P (H₂O) = 24 torr
P (H₂) = P (total) - P (H₂O) = 765 - 24
P (H₂) = 741 torr
It therefore becomes clear that the pressure of H₂(g) is 741 torr
Water forms a covalent bond and oil forms a noncovalent bond
Pollution would go in the form of surface runoff and into rivers and ocean and then disrupt ecosystems because some ecosystems depend on water
Answer
2.7956 * 10^19 photons
Givens
- Wavelength = λ = 525 * 10^-9 meters [1 nmeter = 1*10^-9 meters]
- c = 3 * 10^8 meters
- E = ???
- W = 100 watts
- t = 1 second
- h= plank's Constant = 6.26 * 10^-34 J*s
Formula
E = h * c / λ
W = E / t
Solution
E = 6.26 * 10^-34 j*s * 3 * 10^8 m/s /525 * 10^-9 (m)
The meters cancel out. So do the seconds. You are left with Joules as you should be.
E = 3.577 * 10^-18 Joules
What you have found is the energy of 1 photon.
Now you have to find the Joules from the watts.
W = E/t
100 * 1 second = 100 joules
1 photon contains 3.577 * 10 ^ - 18 Joules
x photon = 100 joules
1/x = 3.577 * 10^-18 / 100 Cross multiply
100 = 3.577 * 10 ^ - 18 * x Divide both sides by 3.577 * 10 ^ - 18
100/3.577 * 10 ^ - 18 = 3.577 * 10 ^ - 18x / 3.577 * 10 ^ - 18
2.7956 * 10^19 photons = x
