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2 years ago

Give two reasons why a luminous flame is not used for heating purposes. (2mks) a

Chemistry

1 answer:

Natali [406]2 years ago

8 0

Answer:

The Two reasons are :-

1. Combustion efficiency

2. Standardization of test conditions as non-luminous flame.

Explanation:

A luminous flame isn't suitable for heating as it gives out soot (A black powdery or flaky substance consisting largely of amorphous carbon, produced by the incomplete burning of organic matter)

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Calculate the vapor pressure at 35ºC of a solution made by dissolving 20.2 g of sucrose (C12H22O11)in 60.5 g of water. The vapor

sukhopar [10]

Answer:

P' = 41.4 mmHg → Vapor pressure of solution

Explanation:

ΔP = P° . Xm

ΔP = Vapor pressure of pure solvent (P°) - Vapor pressure of solution (P')

Xm = Mole fraction for solute (Moles of solvent /Total moles)

Firstly we determine the mole fraction of solute.

Moles of solute → Mass . 1 mol / molar mass

20.2 g . 1 mol / 342 g = 0.0590 mol

Moles of solvent → Mass . 1mol / molar mass

60.5 g . 1 mol/ 18 g = 3.36 mol

Total moles = 3.36 mol + 0.0590 mol = 3.419 moles

Xm = 0.0590 mol / 3.419 moles → 0.0172

Let's replace the data in the formula

42.2 mmHg - P' = 42.2 mmHg . 0.0172

P' = - (42.2 mmHg . 0.0172 - 42.2 mmHg)

P' = 41.4 mmHg

5 0

3 years ago

Calculation of Molar Ratios of Conjugate Base to Weak Acid from pH For a weak acid with a pKa of 6.0, calculate the ratio of con

Free_Kalibri [48]

Explanation:

According to the Handerson equation,

pH = $pK_{a} + log \frac{\text{salt}}{\text{acid}}$

or, pH = $pK_{a} + log \frac{\text{conjugate base}}{\text{acid}}$

Putting the given values into the above equation as follows.

pH = $pK_{a} + log \frac{\text{conjugate base}}{\text{acid}}$

5.0 = 6.0 + log \frac{\text{conjugate base}}{\text{acid}}[/tex]

$log \frac{\text{conjugate base}}{\text{acid}}$ = -1.0

or, $\frac{\text{conjugate base}}{\text{acid}} = 10^{-1.0}$

= 0.1

Therefore, we can conclude that molar ratios of conjugate base to weak acid for given solution is 0.1.

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2 years ago

Match these items with their examples.

kiruha [24]

Here you go! Feel free to ask questions!

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3 years ago

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you are given a solution of lead nitrate. use any of the solution used in this experiment to form a white precipitate of lead ch

Vesnalui [34]

We have as a reagent a salt, lead nitrate (Pb(NO3)2), and an unknown solution that gives us as a product lead chloride (PbCl2). That is, the solution must contain chlorine.

If a chlorine solution is used we will have the following reaction:

$Pb(NO_{3)2}+2Cl^-\rightarrow PbCl_2+2NO^-_3$

So, with a chlorine solution, we will have a white precipitate of lead chloride.

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10 months ago

A consequence of "yo-yo dieting is that A. cholesterol levels will increase. B. A person will develop allergies to certain foods

Tju [1.3M]

the correct option is C.

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2 years ago

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Give two reasons why a luminous flame is not used for heating purposes. (2mks) a​

Give two reasons why a luminous flame is not used for heating purposes. (2mks) a