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Juliette [100K]
3 years ago
15

Give two reasons why a luminous flame is not used for heating purposes. (2mks) a​

Chemistry
1 answer:
Natali [406]3 years ago
8 0

Answer:

The Two reasons are :-

1. Combustion efficiency

2. Standardization of test conditions as non-luminous flame.

Explanation:

A luminous flame isn't suitable for heating as it gives out soot (A black powdery or flaky substance consisting largely of amorphous carbon, produced by the incomplete burning of organic matter)

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How many atoms are present in a sample of Potassium (K) weighing 33.49g?
madam [21]

Answer:

5.158 × 10²³ atoms K

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

33.49 g K

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of K - 39.10 g/mol

<u>Step 3: Convert</u>

<u />33.49 \ g \ K(\frac{1 \ mol \ K}{39.10 \ g \ K} )(\frac{6.022 \cdot 10^{23} \ atoms \ K}{1 \ mol \ K} ) = 5.15797 × 10²³ atoms K

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig figs and round.</em>

5.15797 × 10²³ atoms K ≈ 5.158 × 10²³ atoms K

3 0
3 years ago
PLeas hurry
jeka94
Construction of dam : scarcity of water for animals
4 0
3 years ago
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What happens when exhaled air passes through clear lime water?​
dimulka [17.4K]
Huh what type of question is that?!
3 0
3 years ago
What causes clothes from a dryer to stick together?
leva [86]
Different fabrics rub together, and electrons may rub off 
8 0
3 years ago
Estimate ΔH for the reaction using bond dissociation energies from Table 7.1. Give your answer in kcal. C6H12O6 has five C−C bon
Nat2105 [25]

The equation for the photosynthesis reaction in which carbon dioxide and water react to form glucose is . The hear reaction is the difference between the bond dissociation energies in the products and the bond dissociation energies of the reactants

 

The reactant molecules have 12 C = O, 12 H - O bonds while the product molecules have 5 C - C, 7 C – O, 5 H – O, and 6 O = O bonds. The average bond dissociation energies for the bonds involved in the reaction are 191 for C = O, 112 for H – O, 83 C –C, 99 C – H, 86 C – O, 119 O = O.

 

Substitute the average bond dissociation energies in the equation for and calculate as follows

= [12 (C=O) + 12 (H-O)] – [5(C-C) + 7(C-H) + 7 (C-O) + 5(H-O) + 6(O=O)]

= [12x191 kcal/mol + 12x112 kcal//mol] – [5x83 kcal/mol + 7x99 kcal/mol + 7x86 kcal/mol + 5x112 kcal/mol + 6x119 kcal/mol]

= 3636 kcal/mol – 2984 kcal/mol = 652 kcal/mol x 4.184 Kj/1kcal = 2.73x10^3 kJ/mol

 

So, enthalpy change for the reaction is 652 kcal/mol or 2.73x10^3 kJ/mol

<span> </span>

5 0
3 years ago
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