Answer:
Explanation:
A 12.48 g sample of an unknown metal, heated to 99.0 °C was then plunged into 50.0 mL of 25.0 °C water. The temperature of the water rose to 28.1 Go to calculating final temperature when mixing two samples of water ... Problem #1: A 610. g piece of copper tubing is heated to 95.3 °C and placed in an ... The two rings are heated to 65.4 °C and dropped into 12.4 mL of water at 22.3 °C. ... Problem #4: A 5.00 g sample of aluminum (specific heat capacity = 0.89 J g¯1
Let us assume that there is a 100g sample of Opal. The masses of each element will be:
29.2g Si
33.3g O
37.5g H2O
Now we divide each constituent's mass by its Mr to get the moles present
Si: (29.2 / 28) = 1.04
O: (33.3 / 16) = 2.08
H2O: (37.5 / 18) = 2.08
Now we divide by the smallest number and obtain:
Si: 1
O: 2
H2O: 2
Thus, the empirical formula of Opal is:
SiO2 . 2H2O
Answer:
Option D. ZnCl₂ and H₂
Explanation:
From the question given above, the following equation was obtained:
2HCl + Zn —> ZnCl₂ + H₂
Products =?
In a chemical equation, reactants are located on the left side while products are located on the right side i.e
Reactants —> Products
Now, considering the equation from the question i.e
2HCl + Zn —> ZnCl₂ + H₂
The products are ZnCl₂ and H₂ because from our discussion above, we said that products are only located on the right side of chemical equation.
Thus, option D gives the correct answer to the question.
Answer:
Hope this helps D.
Explanation:
During cellular respiration, glucose is broken down in the presence of oxygen to produce carbon dioxide and water. Energy released during the reaction is captured by the energy-carrying molecule ATP (adenosine triphosphate).
