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ehidna [41]
3 years ago
10

When making a fire, without gas, matches, or a lighter, what are two important things about the wood?

Chemistry
2 answers:
Alexandra [31]3 years ago
6 0

Answer:

The reason wood burns more easily than most metals is because it doesn't actually burn, it vaporizes instead. When wood is heated, the molecules in the wood break down to form flammable gasses, which mix with the air and then burn.Then it takes more heat energy to trigger the reaction with oxygen. The amount of heat produced depends on the molecules that make up the fuel. ... For example, large pieces of wood take a lot longer to absorb heat energy to ignition temperature. A twig catches fire easily because it heats up easily

Explanation:

Allushta [10]3 years ago
5 0

Answer:

that is a solid and that there are other ways to make a fire?

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How many moles of argon would you have if you have 25 L of argon?
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Answer: 39.948 grams

Explanation:

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Argon, or 39.948 grams

4 0
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Carbon exists in nature as three isotopes. Given the atomic masses and relative abundance of the isotopes, what is the average a
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The most abundant carbon isotope is carbon-12.

The relative atomic mass of carbon is 12.011, which is extremely close to 12.0. This means that the masses C-13, and C-14 are practically negligible when contributing to the relative atomic mass of carbon.

the C-12 isotope makes up 98.9% of carbon atoms, C-13 makes up 1.1% of carbon atoms, and C-14 makes up just a trace of carbon atoms as they are found in nature.

6 0
3 years ago
How many atoms are in 175.8 grams of Hg?
dybincka [34]
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Assuming that all the energy given off in the reaction goes to heating up only the air in the house, determine the mass of metha
nirvana33 [79]

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Explanation:

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35.0m\times 35.0m \times 3.2m \times \frac{10^{3}L }{1m^{3} } =3.9 \times 10^{6} L

The moles of air are:

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The heat required to heat the air by 10.0 °C (or 10.0 K) is:

1.7 \times 10^{5}mol \times \frac{30J}{K.mol} \times 10.0 K = 5.1 \times 10^{7}J

Methane's heat of combustion is 55.5 MJ/kg. The mass of methane required to heat the air is:

5.1 \times 10^{7}J \times \frac{1kgCH_{4}}{55.5 \times 10^{6} J } =0.92kgCH_{4}

3 0
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