PLEASE HELPPPPPPP:

Which type of compound has a high melting point, conducts electricity in the molten phase

irina [24]

✅(D) a molecular solid. These compounds have low melting points, low electrical conductivity, etc, so this is the correct answer.

IamSugarBee

3 0

3 years ago

Which of the following provides the best description of the function of genes?

Schach [20]

Answer:

D. Controlling the production of specific proteins.

Explanation:

Genetic material is the main thing that inherited from parents to their offsprings. Gene encodes proteins that will be expressed(produced) when it needed. The protein can be used to build the cell organ, enzyme enzyme that digest food, hormones, and many other things. By inheriting the gene, the offspring will have a similar traits to the parent. The trait can differ a lot for sexual reproduction since only half of each parent gene inherited to the offspring.

5 0

3 years ago

What mass (in g) of potassium chlorate is decomposed if the yield of oxygen gas for the first reaction is 88.6%, if it is known

Ainat [17]

Using the stoichiometry and the number of moles involved in the reaction, The mass of KClO3 decomposed is 63.73 g.

Let us take it up from the second reaction;

Using stoichiometry , the equation of the reaction is;

CH4 + 2O2 ⟶ CO2 + 2H2O

Number of moles of CO2 produced = mass/molar mass

Actual yield of CO2 = 23.6 * 100/77.8 = 30.33 g

Number of moles in 30.33 g of CO2 = 30.33 g/44 g/mol = 0.69 moles

From the reaction equation;

2 moles of O2 yields 1 mole of CO2

x moles of O2 yields 0.69 moles of CO2

x = 2 * 0.69 /1

x = 1.38 moles of O2.

Mass of O2 used = 1.38 moles * 32 g/mol = 44.16 g

This becomes the actual yield of the first reaction.

Theoretical yield of oxygen = 44.16 g * 100/88.6

= 49.84 g of O2

Number of moles of O2 = 49.84 g/32 g/mol = 1.56 moles

Given the reaction equation;

KClO3 ⟶ 2KCl + 3O2

1 mole of KClO3 yields 3 moles of O2

x moles of O2 yields 1.56 moles of O2

x = 1 * 1.56/3

= 0.52 moles of KClO3

Mass of KClO3 decomposed = 0.52 moles * 122.55 g/mol = 63.73 g of KClO3

Learn more: brainly.com/question/9743981

7 0

3 years ago

You use a 15.0 gram piece of aluminum foil to cover a pan in the oven. The specific heat for aluminum is c = 0.900 J/g o C. If t

SVEN [57.7K]

Answer:

Best regards.

Explanation:

Hello,

In this case, we relate the heat, mass, heat capacity and temperature when a thermal change is carried out as shown below:

$Q=mCp(T_{final}-T_{initial})$

Now, for the given data, we compute the absorbed heat (due to the temperature increase) as follows:

$Q=15.0g*0.900\frac{J}{g^oC}*(350^oC-25^oC) \\\\Q=4.39x10^3J=4.39kJ$

Best regards.

8 0

3 years ago

Read 2 more answers

For each of the following balanced chemical equations, calculate how many moles and how many grams of each product would be prod

natima [27]

Answer:

(a)

Moles of ammonium chloride = 0.5 mole

Mass of ammonium chloride formed = 26.7455 g

(b)

Mole of $CS_2$ = 0.125 mole

Mass = Moles * Molar mass = 0.125 * 76.139 g = 9.52 g

Mole of $H_2S$ = 0.25 mole

Mass = Moles * Molar mass = 0.25 * 34.1 g = 8.525 g

Explanation:

(a)

For the first reaction:-

$NH_3_{(g)}+HCl_{(g)}\rightarrow NH_4Cl_{(s)}$

The mole ratio of the reactants = 1 : 1

0.5 moles of ammonia react with 0.5 moles of hydrochloric gas to give 0.5 moles of ammonium chloride

So, Moles of ammonium chloride formed = 0.5 moles

Molar mass of ammonium chloride = 53.491 g/mol

Mass = Moles * Molar mass = 0.5 * 53.491 g = 26.7455 g

(b)

For the first reaction:-

$CH_4_{(g)}+4S_{(s)}\rightarrow CS_2_{(l)}+2H_2S_{(g)}$

The mole ratio of the reactants = 1 : 4

It means

0.5 moles of methane react with 2.0 moles of sulfur to give 0.5 moles of Carbon disulfide and 1.0 moles of hydrogen sulfide gas.

But available moles of S = 0.5 moles

Limiting reagent is the one which is present in small amount. Thus, S is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

4 moles of S produces 1 mole of $CS_2$

Thus,

0.5 moles of S produces $\frac{1}{4}\times 0.5$ mole of $CS_2$

Mole of $CS_2$ = 0.125 mole

Molar mass of $CS_2$ = 76.139 g/mol

Mass = Moles * Molar mass = 0.125 * 76.139 g = 9.52 g

4 moles of S produces 2 moles of $H_2S$

Thus,

0.5 moles of S produces $\frac{2}{4}\times 0.5$ mole of $H_2S$

Mole of $H_2S$ = 0.25 mole

Molar mass of $H_2S$ = 34.1 g/mol

Mass = Moles * Molar mass = 0.25 * 34.1 g = 8.525 g

7 0

3 years ago