Conduction is your answer
Answer:
468 h
Explanation:
Let's consider the reduction of chromium (III) to chromium that occurs in the electrolytic purification.
Cr³⁺ + 3 e⁻ → Cr
We can establish the following relations.
- 1 kg = 1,000 g
- The molar mass of Cr is 52.00 g/mol
- 1 mole of Cr is deposited when 3 moles of electrons circulate
- The charge of 1 mole of electrons is 96,468 c (Faraday's constant)
- 1 A = 1 c/s
- 1 h = 3,600 s
The hours that will take to plate 11.5 kg of chromium onto the cathode if the current passed through the cell is held constant at 38.0 A is:

Molecules of SO₃ : 4.214 x 10²³
<h3>Further explanation
</h3>
The reaction equation is the chemical formula of reagents and product substances
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products
Reaction(balanced)
2SO₂(g) + O₂(g) → 2SO₃(g)
mol SO₃ :


number of molecules :
1 mol = 6.02 x 10²³ particles(atoms, molecules,ions)

Answer:
The molarity of the chromium(III) acetate solution 0.3982 M.
0.3982 M is the concentration of the chromium(III) cation.
1.1946 M is the concentration of the acetate anion.
Explanation:

Mass of chromium(III) acetate = 22.8 g
Molar mass of chromium(III) acetate = 229 g/mol
Total volume of the solution of chromium(III) acetate = V = 250 mL = 0.250 L
1 mL = 0.001 L
The molarity of the chromium(III) acetate solution :
![[Cr(CH_3COO)_3]=\frac{22.8 g}{229 g/mol\times 0.250 L}=0.3982 M](https://tex.z-dn.net/?f=%5BCr%28CH_3COO%29_3%5D%3D%5Cfrac%7B22.8%20g%7D%7B229%20g%2Fmol%5Ctimes%200.250%20L%7D%3D0.3982%20M)
The molarity of the chromium(III) acetate solution 0.3982 M.

According to reaction, 1 mole of chromium(III) acetate gives 1 mole of chromium(III) ions and 3 moles of acetate ions.
So ![[Cr^{3+}]=[Cr(CH_3COO)_3]=0.3982 M](https://tex.z-dn.net/?f=%5BCr%5E%7B3%2B%7D%5D%3D%5BCr%28CH_3COO%29_3%5D%3D0.3982%20M)
![[CH_3COO^-]=3\times [Cr(CH_3COO)_3]=3\times 0.3892 M=1.1946 M](https://tex.z-dn.net/?f=%5BCH_3COO%5E-%5D%3D3%5Ctimes%20%5BCr%28CH_3COO%29_3%5D%3D3%5Ctimes%200.3892%20M%3D1.1946%20M)
0.3982 M is the concentration of the chromium(III) cation.
1.1946 M is the concentration of the acetate anion.
They move faster at a higher temperature i believe. i hope this helps