You just find the area of the triangle, and do that times 4 that number. The formula for finding the area of a triangle is half the base times the height 3 * 9 = 27. So the area of the triangle is 27 and the area of all 4 of the triangles would just be 27 * 4 = 108. Now for the square. Formula for finding the area of a square is length times width which would be 6 * 6 = 36. So then you do 36 + 108 = 144
So the area of the net is 144M
Answer:
OPTION B IS YOUR ANSWER.
You know its a quadratic when the second difference of each y value is same.
Here's what I mean.
Option B
First all x values differ by 1. So we're good on those.
Now for the y values
Which are
3, -1, -3, -3, -1
find the difference between the second and first fod each... Then do this a second time.
If it gives the same value for all the second differences... Then its quadratic.
-1-3 = -4
-3-(-1) = -3 + 1 = -2
-3-(-3) = -3 + 3 = 0
-1-(-3) = -1 + 3 = 2.
The values are -4, -2, 0, 2.
Now find the difference of these(2nd - 1st)
-2-(-4) = -2 + 4 = 2
0-(-2)= 0 + 2 = 2
2 - 0 = 2
Since all second differences gave 2 as their answer....
Option B is your Quadratic Function!!!
Hope this helps!
Answer:
120
Step-by-step explanation:
well it have to be a nuber by 5, 10 etc
also even too
so that be 120
To solve this problem, we have to substitute in the value of -6 for each x in the expression. This is shown below:
(x² - 3)/(x+3) = ((-6)² - 3)/((-6) + 3)
To simplify this seemingly daunting expression, we should first simplify the exponents in the numerator. This is because of the order of operations, outlined by PEMDAS, which states that we should compute numbers in parentheses first, exponents next, then multiplication and division, and finally addition and subtraction.
((-6)² - 3)/((-6) + 3) = (36-3)/(-6+3)
Now, we can perform the addition and subtraction in the numerator and denominator because they are both in parentheses.
(36-3)/(-6+3) = 33/-3
Finally, we can perform the last operation of division.
-11
Therefore, your answer is -11.
Hope this helps!