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2 years ago

Can someone help please

Chemistry

2 answers:

timama [110]2 years ago

3 0

Answer:

To achieve stability

Explanation:

Chemical reactions happen so that the atoms of the elements involved in the chemical reaction will become stable and therefore achieve stability.

miss Akunina [59]2 years ago

3 0

Answer:

to form new compounds

Explanation:

Chemical reactions occur when two substances interact to form new compounds or molecules.

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An observation balloon was filled with 0.50 atmospheres of Helium, 54.0 mm Hg of Nitrogen, and 0.400 atmospheres of Hydrogen. Wh

noname [10]

Answer:

the pressure would be 0.9 atmospheres

Explanation:

you just gotta add the presures for each of the gases that are added

7 0

3 years ago

Calculate the mass (g) of 1.5 moles of Sulfur.

just olya [345]

Answer:

48 g S

Explanation:

Step 1: Define

Molar Mass of Sulfur (S) - 32.07 g/mol

Step 2: Use Dimensional Analysis

$1.5 \hspace{3} mol \hspace{3} S(\frac{32.07 \hspace{3} g \hspace{3} S}{1 \hspace{3} mol \hspace{3} S} )$ = 48.105 g S

Step 3: Simplify

We have 2 sig figs.

48.105 g S ≈ 48 g S

7 0

3 years ago

Answer what you can please. The most accurate will get brainliest. High rating and Many thanks.

Elina [12.6K]

The correct answer for #8 is:

C. The original pattern of the light is distorted.

3 0

4 years ago

Powerful_____________________________ in nature, such as wind, temperature, and ice, can exert enough pressure to cause the wall

stich3 [128]

Answer:

I believe forces would be the word you are looking for.

Explanation:

I hope this is what you needed, have a great day! (;

3 0

3 years ago

It take 38.70cm³ of 1.90m NaoH to neutralize 10.30cm³ of H2so4 in a battery, calculate the molar concentration of H2so4

zlopas [31]

Answer:

$M_{acid}=3.57M$

Explanation:

Hello there!

In this case, since this acid-base neutralization is performed in a 1:2 mole ratio of acid to base as the former is a diprotic acid (two hydrogen ions in the molecule), we can write the following equation:

$2M_{acid}V_{acid}=M_{base}V_{base}$

In such a way, we can solve for the molarity of the acid, given the molarity and concentration of the NaOH base and the volume of the acid:

$M_{acid}=\frac{M_{base}V_{base}}{2V_{acid}}$

Thus, we plug in the given data to obtain:

$M_{acid}=\frac{38.70cm^3*1.90M}{2(10.30cm^3)} \\\\M_{acid}=3.57M$

Best regards!

8 0

3 years ago