We have that the correct wedge and dash conformation for the following Newman projection is
IV
From the Diagrams above
Two CH_3 groups points on opposite sides in plane
Two Br are on same side of plane
Two H also on same side of the plane so the plausible structure is IV
Therefore
The Correct option is IV
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d. Fe(s) and Al(s)
<h3>Further explanation</h3>
In the redox reaction, it is also known
Reducing agents are substances that experience oxidation
Oxidizing agents are substances that experience reduction
The metal activity series is expressed in voltaic series
<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au </em>
The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent
The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent
So that the metal located on the left can push the metal on the right in the redox reaction
The electrodes which are easier to reduce than hydrogen (H), have E cells = +
The electrodes which are easier to oxidize than hydrogen have a sign E cell = -
So the above metals or metal ions will reduce Pb²⁺ (aq) will be located to the left of the Pb in the voltaic series or which have a more negative E cell value (greater reduction power)
The metal : d. Fe(s) and Al(s)
Fe3N2, also known as Iron (II) nitride, is an ionic compound.
Ionic compounds are compounds that consists of metals and non-metals bonded with ionic bonds. The metal ion gives up electron(s) to the non-metals.
Since iron is a metal and nitrogen is an non-metal, the bond they would form would be an ionic bond. Iron gives up 2 electrons to form iron(II) ion, while nitrogen gains 3 electrons to form nitride ion. Since one iron cannot let a nitrogen gain 3 electrons, so in the compound, there would be 3 iron (ii) ions that has given up 6 electrons in total while 2 nitride ions have gained 6 electrons in total.
Answer: 2738
Explaining: you gotta add
<h3>Answer:</h3><h2>NADPH and ATP</h2><h3>Explanation:</h3>
When the light absorbs by the photosynthetic apparatus, the water molecules break down to produce essential material to continue the photosynthetic cycle as electron and H-ions. The H-ions becomes stored in thylakoid chamber and passed through the ATP synthetic machines to refill the ADP or AMP molecules. The generated electron passes through the various stages of photosynthetic series to finally produce the NADPH which also acts as energy transfer compound. At the PSI, the electron transfer to the NADP to generate NADPH.
