Question

You have a red ballooe that has a volume of 20 liters, a pressure of 1.5 atmospheres and a temperature of 28 C. What is the volume of the balloon if you change the pressure to 5 atmospheres and change the temperature to S0°C Oa.1.07 L Ob3.0 L 0.64 L O d.o.42 L

Answer 1

Explanation:

The given data is as follows.

 $P_{1}$ = 1.5 atm,     $V_{1}$ = 20 L,  $T_{1}$ = (28 + 273) K = 301 K

   $P_{2}$ = 5 atm,     $V_{2}$ = ?,  $T_{2}$ = (50 + 273) K = 323 K

Formula to calculate the volume will be as follows.

         $\frac{P_{1} \times V_{1}}{T_{1}}$ = $\frac{P_{2} \times V_{2}}{T_{2}}$

Putting the given values into the above formula as follows.

        $\frac{P_{1} \times V_{1}}{T_{1}}$ = $\frac{P_{2} \times V_{2}}{T_{2}}$  

        $\frac{1.5 atm \times 20 L}{301 K}$ = $\frac{5 atm \times V_{2}}{323 K}$  

                 $V_{2}$ = 0.64 L

Thus, we can conclude that the change in volume of the balloon will be 0.64 L.