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3 years ago

13

An observation balloon was filled with 0.50 atmospheres of Helium, 54.0 mm Hg of Nitrogen, and 0.400 atmospheres of Hydrogen. Wh

at pressure in atmospheres was the balloon filled to?

1 answer:

noname [10]3 years ago

7 0

Answer:

the pressure would be 0.9 atmospheres

Explanation:

you just gotta add the presures for each of the gases that are added

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In reality, energy conversion from burning fuel is never 100% efficient. Significant loss of energy due to heating occurs. If th

algol [13]

Answer:

Electrical energy = 130000000 J and Heat energy = 520000000 J

Explanation:

Multiply the amount of joules from the last question (650000000) by .20 and .80. (Which are the percentages)

6 0

3 years ago

Ammonia, nh3, is a weak base with a kb = 1.8 x 10-5. in a 0.8m solution of ammonia, which has a higher concentration: ammonia (n

insens350 [35]

Answer is: concentration ammonia is higher than concentration of ammonium ion.
Chemical reaction of ammonia in water: NH₃ + H₂O → NH₄⁺ + OH⁻.
Kb(NH₃) = 1,8·10⁻⁵.
c₀(NH₃) = 0,8 mol/L.
c(NH₄⁺) = c(OH⁻) = x.
c(NH₃) = 0,8 mol/L - x.
Kb = c(NH₄⁺) · c(OH⁻) / c(NH₃).
0,000018 = x² / 0,8 mol/L - x.
solve quadratic equation: x = c(NH₄⁺) = 3,79·10⁻³ mol/L.

7 0

3 years ago

When this candle is burned it seems to disappear over a period of time. In actuality, the candle is being converted to smoke,ash

Hitman42 [59]

C.the law of chemical reactions

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2 years ago

How many moles of oxygen are required to react with methanol in order to produce 13 moles of formaldehyde?

ddd [48]

Answer:

6.5 moles of Oxygen are required

Explanation:

Based on the reaction:

CH3OH + 1/2 O2 → CH2O + H2O

1 mole of methanol reacts with 1/2 moles O2 to produce 1 mole of formaldehyde and 1 mole of water.

Thus, to produe 13 moles of formaldehyde, CH2O, are needed:

13 moles CH2O * (1/2mol O2 / 1mol CH2O) =

<h3>6.5 moles of Oxygen are required</h3>

3 0

3 years ago

A specific steroid has a λmax of 257 nm and a molar absorptivity ε of 11 , 500 L mol − 1 cm − 1 . What is the concentration of t

joja [24]

Answer:

$7.83\times 10^{-6} M$ is the concentration of the compound in a solution.

Explanation:

Using Beer-Lambert's law :

Formula used :

$A=\epsilon \times C\times l$

Where:

A = absorbance of solution

C = concentration of solution

l = path length

$\epsilon$ = molar absorptivity coefficient

We have:

C = ? , l = 1.00 cm, A = 0.090

$\epsilon = 11,500 L/(mol cm)$

$C=\frac{A}{\epsilon l}=\frac{0.090}{11,500 L/(mol cm)\times 1.00 cm}$

$C=7.83\times 10^{-6} M$

$7.83\times 10^{-6} M$ is the concentration of the compound in a solution.

6 0

3 years ago