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kow [346]
3 years ago
15

Can someone pls help me with this one problem

Mathematics
2 answers:
babymother [125]3 years ago
8 0

Answer:

295

Step-by-step explanation:

because 407-112 is 295

sweet-ann [11.9K]3 years ago
5 0

Answer:

45,584

Step-by-step explanation:

hope this helps

sorry if wrong

#Virgo2007

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Can someone explain how to do #3?
dsp73

\displaysyle (\sqrt 2)^{3}=(2^{\frac{1}{2}})^3=2^{\frac{1}{2} \cdot 3}=2^{\frac{3}{2}}=\sqrt {2^3}=\sqrt 8

√8 is between 2 and 3, because 2²=4<8, but 3²=9>8. Also, our value is closer to 3 than to 2, so it is more than 2.5 and we have C and D options left.

Among these two numbers we find the one which is closer to √8.

C. 27=√729 ⇒ 2.7=√7.29

D. 28=√784 ⇒ <u>2.8=√7.84</u>

Hence our answer is D) 2.8

5 0
4 years ago
Read 2 more answers
List the elements in each set.
atroni [7]

Answer:

2

Step-by-step explanation:

1+1=2

8 0
3 years ago
A football player gained two yards on one play on the next play he gained 5 ft was his gain greater on the first play or the sec
saveliy_v [14]
The gain was greater on the first play.

1 yard=3 ft
2yards times 3= 6ft

6ft>5ft


Hope this is helpful!
4 0
3 years ago
5. The number of solutions to |x - 8| + b = c depends on the relationship between b and c How do b and compare if there are two
Furkat [3]

Answer:

X= -b+c+8

X= b-c+8

solutions

5 0
3 years ago
A building is 30 feet high. At a distance away from the building, an observer notices that the angle of elevation to the top of
yKpoI14uk [10]

Answer

As per the statement:

Height of the building(h)= 30 feet

Angle of elevation (\theta)= 41°

We have to find the distance of observer from the base of the building.

Using tangent ratio:

\tan \theta= \frac{\text{Opposite side}}{\text{Adjacent side}}

You can see the diagram as shown below.

Opposite side = height of the building = 30 feet.

Adjacent side = distance of observer from the base of the building = x (let)

Then;

\tan 41^{\circ}= \frac{30}{x}

0.86928673781 = \frac{30}{x}

By cross multiply we have;

0.86928673781x = 30

Divide by 0.86928673781 both sides we get;

x = 34.51 m

Therefore, the distance of observer from the base of the building is 34.51 m


7 0
3 years ago
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