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3 years ago

What is the value of coefficient of friction force

Physics

2 answers:

san4es73 [151]3 years ago

3 0

Answer:

<h2>There is a frictional force between two objects that are not in relative motion. Such a force is called the static friction force.</h2><h2>There is a frictional force between two objects that are not in relative motion. Such a force is called the static friction force....</h2><h2>There is a frictional force between two objects that are not in relative motion. Such a force is called the static friction force....Friction coefficients.</h2><h2>There is a frictional force between two objects that are not in relative motion. Such a force is called the static friction force....Friction coefficients.MATERIAL S K</h2><h2>There is a frictional force between two objects that are not in relative motion. Such a force is called the static friction force....Friction coefficients.MATERIAL S KMetal on leather 0.6 0.5</h2><h2>There is a frictional force between two objects that are not in relative motion. Such a force is called the static friction force....Friction coefficients.MATERIAL S KMetal on leather 0.6 0.5Wood on leather 0.5 0.4</h2><h2>There is a frictional force between two objects that are not in relative motion. Such a force is called the static friction force....Friction coefficients.MATERIAL S KMetal on leather 0.6 0.5Wood on leather 0.5 0.4Rubber on concrete, dry 0.9 0.7</h2><h2>There is a frictional force between two objects that are not in relative motion. Such a force is called the static friction force....Friction coefficients.MATERIAL S KMetal on leather 0.6 0.5Wood on leather 0.5 0.4Rubber on concrete, dry 0.9 0.7wet 0.7 0.57</h2>

Explanation:

<h2>Greetings, I'm from my beloved Mexico</h2>

Sav [38]3 years ago

3 0

The coefficient of friction depends on the objects that are causing friction. The value is usually between 0 and 1 but can be greater than 1. A value of 0 means there is no friction at all between the objects; such is possible with Superfluidity.

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igor_vitrenko [27]

Answer:

$= 5.241 \times 10^{-5} m$

Explanation:

Given:

Length of cylinder is, L = 0.27 m

Outer radius of cylinder is, r_out = 1.12×10^{-2} m

Inner radius of cylinder is, r_in = 3.9×10^{-3} m

Mass of person, m = 60 kg

Young's modulus , Y = 9.4×10^9 N/m2

(a)

Compressional strain of humerous is,

$Strain = \frac{Stress}{Young's\ modulus}$

$\frac{\Delta L}{L_0} = \frac{\frac{F}{A}}{Y}$

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(b) Let assume that humerous is compressed by ΔL

Since, strain = ΔL/L0

$(1.80 \times 10^{-4} m) = ΔL / 0.29 m$

Thus,

$ΔL = (4.56 \times 10^{-4} m)(0.29 m)$

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C. located in front of the lens

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3 years ago

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1. What is the wave speed of a wave that has a frequency of 100 Hz and a wavelength of 0.30 m?

aivan3 [116]

Answer:

1. v = 30 m/s

2. v = 5 m/s

3. f = 40 Hz

4. f = 400 Hz

5. f = 300 Hz

6. λ = 0.772 m

7. λ = 0.386 m

8. λ = 0.625 m

9. v = 100 m/s

10. v = 50 m/s

Explanation:

The relationship between frequency, wavelength, and speed of a wave is given by the following formula:

$v = f\lambda$

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λ = 0.3 m

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v = (100 Hz)(0.3 m)

<u></u>

f = 50 Hz

λ = 0.1 m

v = (50 Hz)(0.1 m)

<u></u>

v = 20 m/s

λ = 0.5 m

$f = \frac{v}{\lambda} = \frac{20\ m/s}{0.5\ m}$

<u></u>

v = 80 m/s

λ = 0.2 m

$f = \frac{v}{\lambda}=\frac{80\ m/s}{0.2\ m}$

<u></u>

v = 120 m/s

λ = 0.4 m

$f = \frac{v}{\lambda}=\frac{120\ m/s}{0.4\ m}$

<u></u>

v = 340 m/s

f = 440 Hz

$\lambda = \frac{v}{f}=\frac{340\ m/s}{440\ Hz}\\$

<u></u>

v = 340 m/s

f = 880 Hz

$\lambda = \frac{v}{f}=\frac{340\ m/s}{880\ Hz}\\$

<u></u>

v = 250 m/s

f = 400 Hz

$\lambda = \frac{v}{f}=\frac{250\ m/s}{400\ Hz}\\$

<u></u>

f = 50 Hz

λ = 2 m

v = (50 Hz)(2 m)

<u></u>

10.

f = 100 Hz

λ = 0.5 m

v = (100 Hz)(0.5 m)

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Answer:

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What is the value of coefficient of friction force​

What is the value of coefficient of friction force