Answer:
69.2 Nm
Explanation:
Since torque, τ = Fd where F = force and d = distance of force from center of wheel.
The torque due to the clockwise force F' = 43.2 N at a distance d' = radius of wheel = 2.42 m (since it is at the end of the wheel) is τ' = F'd' = 43.2 N × 2.42 m = 104.544 Nm. Since this force is counterclockwise, the torque is positive. So, τ' = 104.544 Nm
The torque due to the force F" = 67.8 N at a distance d" = 0.522 m from center of wheel is τ" = F"d" = 67.8 N × 0.522 m = 35.3916 Nm. Since this force is counterclockwise, the torque is negative. So, τ" = -35.3916 Nm
The net torque on the wheel τ = τ' + τ"
= 104.544 Nm + (-35.3916 Nm)
= 104.544 Nm - 35.3916 Nm
= 69.1524 Nm
≅ 69.2 Nm
