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Sedaia [141]
3 years ago
8

1 kilogram equals how many grams

Physics
1 answer:
Rudiy273 years ago
6 0
One kilogram equals 1000 grams
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(a) two protons in a molecule are 4.50 10-10m apart. find the magnitude of the electric force exerted by one proton on the other
Anuta_ua [19.1K]

Answer:

a)  1. 1365 × 10⁻⁹N

b) 9.1862 × 10⁻⁴⁶N

c) 8.61 × 10⁻¹¹C/Kg

Explanation:

Ke = 8.99× 109 N.m2 / C2 ,      G = 6.67 × 10-11 N. m2 / kg2

a)  F = Ke . q₁.q₂/r²  

=  (8.99× 109 N.m2 / C2 ) ×(1.60×10⁻¹⁹C)²/(4.50×10⁻¹⁰C)²

= 1. 1365 × 10⁻⁹N

b)  

F = Gm₁m₂/r²

= (6.67× 10⁻¹¹)×(1.67×10⁻²⁷)²/(4.50×10⁻¹⁰)²

= 9.1862 × 10⁻⁴⁶N

The electric force is larger by 8.0497 ×10³⁷ times

c)

if Keq₁q₂/r² Gm₁m₂/r²,

with q₁=q₂ = q,  and m₁ =m₂ = m

Then q/m =\sqrt{G/M} = \sqrt{(6.67 X 10^{-11} } /8.89 X 10^{9}

= 8.61 × 10⁻¹¹C/Kg

8 0
3 years ago
HELP ME ANSWER THIS PLZ I WILL GIVE BRAINLIEST
disa [49]

Answer:

In mitosis, the products are identical to the parent cell, while in meiosis the products are different from the parent cell.

Explanation:

Mitosis replicates DNA at the beginning of the process, so it's always the same, but Meiosis uses a special process called crossing over which causes two chromosomes to swap information, which means that the DNA has changed.

5 0
3 years ago
Experimenting with free fall, Mariana observes that her baseball takes 1.5 s to travel the last 30m before hitting the ground. F
Art [367]

Answer:

37.8 m

Explanation:

At point 0, the ball is at height y₀.

At point 1, the ball is at height 30 m.

At point 2, the ball is at height 0 m.

Given:

y₁ = 30 m

y₂ = 0 m

v₀ = 0 m/s

a = -10 m/s²

t₂ − t₁ = 1.5 s

Find: y₀

Use constant acceleration equation.

y = y₀ + v₀ t + ½ at²

Evaluate at point 1.

y₁ = y₀ + v₀ t₁ + ½ at₁²

30 m = y₀ + (0 m/s) t₁ + ½ (-10 m/s²) t₁²

30 = y₀ − 5t₁²

Evaluate at point 2.

y₂ = y₀ + v₀ t₂ + ½ at₂²

0 m = y₀ + (0 m/s) t₂ + ½ (-10 m/s²) t₂²

0 = y₀ − 5t₂²

y₀ = 5t₂²

Substitute:

y₀ = 5 (1.5 + t₁)²

y₀ = 5 (2.25 + 3t₁ + t₁²)

y₀ = 11.25 + 15t₁ + 5t₁²

30 = 11.25 + 15t₁ + 5t₁² − 5t₁²

30 = 11.25 + 15t₁

t₁ = 1.25

30 = y₀ − 5t₁²

30 = y₀ − 5(1.25)²

y₀ ≈ 37.8

4 0
4 years ago
If you are pushing on a box with a force of 20 N and there is a 7 N force on the box due to sliding friction, what is the net fo
vovangra [49]

Answer:

13 N

Explanation:

The Net Force of an object should be the difference between the forces applied to the object if the object is not in equilibrium. This object is not in equilibrium so therefore by finding the difference between the forces, you will find your answer. 20 N - 7 N = 13 N.

6 0
3 years ago
Read 2 more answers
A resistance training system that is a variation of circuit training and that alternates upper body and lower body exercises thr
dlinn [17]

Answer:

Peripheral heart action.

Explanation:

The Peripheral heart action purpose is to keep the blood circulation throughout the body at time of workout.

This is specially proceed through the small central muscles which goes around your heart.

After that it is followed by the peripheral muscles which lies in the arms, legs and in the abs part.

6 0
4 years ago
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