Question

Simplify and factor if necessary​

Answer 1

Hello there today we will solve your problem, we will need to factorize btw...

${\huge{\boxed{\mathfrak{Equation}}}$

${\big{\boxed{\frac{x^2-5x+4}{x^2-4x}}}}$

First we will factor $x^2-5x+4$, which gives us $\left(x-1\right)\left(x-4\right)$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\frac{\left(x-1\right)\left(x-4\right)}{x^2-4x}$

factorize $x^2-4x$ giving us $x\left(x-4\right)$

$\frac{\left(x-1\right)\left(x-4\right)}{x\left(x-4\right)}$

cancel the common factor $x-4$

and we get $\frac{x-1}{x}$