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2 years ago

Describe and correct the error in

Mathematics

1 answer:

spayn [35]2 years ago

4 0

make the y int -4 because it passes through (0,-4). to make perpendicular, apply same slope to new equation but change sign

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for the following two numbers, find two factors of the first number such that their product is the first number and their sum is

zepelin [54]

You can make some algebraic equations and solve it.
The first would be:
$x \times y = - 21$
The second would be
$x + y = - 4$
You can then rearrange the second into
$x = - 4 - y$
And subsitute it into the first like so:
$( - y - 4) \times y = - 21$
After that, distribute the y into the parantheses.
${ - y}^{2} - 4y = - 21$
Subtract the 21 on both sides and multiply by -1 on both sides:
${ - y}^{2} - 4y + 21 \\ {y}^{2} + 4y - 21$
You then can factor it into:
$(y + 3) \times (y - 7) = 0$
With Zero Product Property, we can determine y to be either -3 and 7. Since the variables are interchangable, you can say the same about x, just that whatever x is, y must be the other value.

Thus, the answer is 7 and -3.

5 0

3 years ago

6) Solve for x. 2/3 (x + 7) = 10 A)22 B)8 C)- 1 /3 D)41/ 3

Amiraneli [1.4K]

For this case we must find the value of the variable "x" of the following equation:

$\frac {2} {3} (x + 7) = 10$

We multiply by 3 on both sides of the equation:

$2 (x + 7) = 30$

We divide between 2 on both sides of the equation:

$(x + 7) = 15\\x + 7 = 15$

We subtract 7 on both sides of the equation:

$x = 8$

Answer:

Option B

7 0

3 years ago

PLEASE HELP ME! FAST

IceJOKER [234]

The quadrants in which all the coordinates given are located is; As explained below.

<h3>How to Identify Quadrants in coordinates?</h3>

1) (2, 4) is located in Quadrant I where both x and y-values are positive.

2) (0, -3) is located in Quadrant II where x - values are positive but y-values are negative.

3) (-1, 1/2) is located in Quadrant IV.

4) (-2 1/2, -7) is located in Quadrant III where x and y values are both negative.

5) (0, 6) is located in Quadrant I where both x and y-values are positive.

6) (-5, 0) is located in Quadrant IV where x is negative but y is positive.

Read more about Quadrant Coordinates at; brainly.com/question/863849

#SPJ1

7 0

1 year ago

The expression 3x2−5x2simplifies to −2x2 is this true?

Helga [31]

Answer:

I dont think so I would look at it as how did they get the -2

5 0

3 years ago

Read 2 more answers

a rectangle prism has a volume of 3x^2 + 18x+ 24. its base has a length of x + 2 and width of 3, what expression represents the

OlgaM077 [116]

$\bf \textit{volume of a rectangular prism}\\\\
V=lwh\qquad 
\begin{cases}
l=x+2\\
w=3\\
V=3x^2 + 18x+ 24
\end{cases}\implies \cfrac{V}{lw}=h
\\\\\\
\cfrac{3x^2 + 18x+ 24}{3(x+2)}=h\implies \cfrac{\underline{3}(x^2 + 6x+ 8)}{\underline{3}(x+2)}=h
\\\\\\
\cfrac{(x+4)\underline{(x+2)}}{\underline{(x+2)}}=h\implies x+4=h$

6 0

3 years ago