There are 3 consecutive odd integers with a sum of 45. What is the greatest of the 3<br> integers

Find the areas of the sectors formed by ABC

Amanda [17]

Answer:

33.51 in^2

Step-by-step explanation:

Find the area of the circle:

A = πr^2

A = π * 8^2

A = 64π = 201.06 in^2

Find the area of the 60 deg slice:

A * 60/360 = 33.51 in^2

Leave a thanks and mark brainliest if this helped

6 0

3 years ago

I don't even know where to start on this problem?

velikii [3]

I think you have to count 85 and go down like 85 86 87so the answer is 15

7 0

3 years ago

What would be the correct notation for the following line

natima [27]

Answer:

Its A :))

Step-by-step explanation:

4 0

2 years ago

1,200 and 11 and you will get 13,200

VLD [36.1K]

Answer:

That is true!

$1,200 * 11 = 13,200$

Let me know if you need more help with multiplication. I may be able to help.

Have a great day.

7 0

2 years ago

If a scalene triangle has its measures 4 m, 11 m and 8 m, find the largest angle.

soldier1979 [14.2K]

Answer:

129.8 approximately

Step-by-step explanation:

So this sounds like a problem for the Law of Cosines. The largest angle is always opposite the largest side in a triangle.

So 11 is the largest side so the angle opposite to it is what we are trying to find. Let's call that angle, X.

My math is case sensitive.

X is the angle opposite to the side x.

Law of cosines formula is:

$x^2=a^2+b^2-2ab \cos(X)$

So we are looking for X.

We know x=11, a=4, and b=8 (it didn't matter if you called b=4 and a=8).

$11^2=4^2+8^2-2(4)(8)\cos(X)$

$121=16+64-64\cos(X)$

$121=80-64\cos(X)$

Subtract 80 on both sides:

$121-80=-64\cos(X)$

$41=-64\cos(X)$

Divide both sides by -64:

$\frac{41}{-64}=\cos(X)$

Now do the inverse of cosine of both sides or just arccos( )

[these are same thing]

$\arccos(\frac{-41}{64})=X$

Time for the calculator:

X=129.8 approximately

3 0

3 years ago

There are 3 consecutive odd integers with a sum of 45. What is the greatest of the 3 integers