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Sindrei [870]
2 years ago
6

What is the range of the function g(x) = [X – 12 – 2? o tyy-2) OVY 2-2) Oviy> 12) O y 2 12)​

Mathematics
1 answer:
oksano4ka [1.4K]2 years ago
3 0

The range of the function is: \{y | y \ge -2 \}

<h3>What is the range of a function?</h3>

The range of a function is the set of output values the function can take

The function is given as:

g(x) = |x - 12| -2

The above function is an absolute value function;

And it is represented as:

g(x) = a|x - h| + b

When a is positive, then the range of the function is:

y \ge b

By comparison, we have:

a =1

b = -2

Hence, the range of the function is: \{y | y \ge -2 \}

Read more about range at:

brainly.com/question/6615538

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295000

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Katyanochek1 [597]

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2 years ago
Read 2 more answers
ABDE is a rectangle ED is 8cm BDC is a right-angled triangle bc is 4.5cm ABC is a straight line the area of the rectangle abde i
Gnesinka [82]

Answer:

11.25cm^2

Step-by-step explanation:

given the area of the rectangle as 40cm^2, we can get the width of the rectangle.

Area =Length x width

40cm^2 = 8cm x width

we can divide both sides 8 to be left with the width

40/8 = 5cm

so the width is 5cm which is equal to the height of the triangle.

Area of BDC = 1/2 x base x height

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=11.25cm^2

5 0
2 years ago
H 0 : μ ≥ 25 H 1 : μ &lt; 25 Your sample consists of 28 subjects, with a mean of 23.2 and standard deviation of 8.6. Calculate t
kykrilka [37]

Answer:

The test statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

And replacing we got:

t=\frac{23.2-25}{\frac{8.6}{\sqrt{28}}}=-1.11    

Step-by-step explanation:

Information given

\bar X=23.6 represent the sample mean

s=8.6 represent the sample standard deviation

n=28 sample size  

\mu_o =25 represent the value that we want to test

t would represent the statistic

System of hypothesis

We want to test if the true mean is lower than 25, the system of hypothesis would be:  

Null hypothesis:\mu \geq 25  

Alternative hypothesis:\mu < 25  

The test statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

And replacing we got:

t=\frac{23.2-25}{\frac{8.6}{\sqrt{28}}}=-1.11    

7 0
3 years ago
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