2x+3y= -17
5x+2y= -4
You must cancel either the x or y out to solve so i'm going to cancel the x.
-5(2x+3y= -17)
2(5x+2y= -4)
This simplifies to:
-15x -15y=85
15x+4y= -8
The -15x and 15x cancel out leaving you:
-15y=85
4y= -8
You add them top numbers by the bottom and get:
-11y=77
Then divide by -11 to get y by its self.
y= -7
Now that you know what y is just plug it in to either original problem. I will use the second one.
5x + 2(-7) = -4
5x -14 = -4
5x = 10
x = 2
So the answer is (2,-7) or x=2 and y=-7
Answer:
c
Step-by-step explanation:
your right
If all three side lengths are INTEGERS and form PYTHAGOREAN TRIPLE then we know decimals are not allowed
if 24 and 51 are both legs then

x = 3177
and squre root of that gives us 56.364.... NOT an integer
So that means one of them is not a leg and since hypotenuse is longer than both legs, 51 must be the hypotenuse so to get the third side
![51^{2} - 24^{2} = x^{2}[tex] [tex] x^{2}](https://tex.z-dn.net/?f=%2051%5E%7B2%7D%20-%20%2024%5E%7B2%7D%20%20%3D%20%20x%5E%7B2%7D%5Btex%5D%20%5Btex%5D%20x%5E%7B2%7D%20)
=2025
x=45, leg B
The answer is D since
4*4=16
16*4=64
64*4=256