Answer:

Explanation: For this, it is often best to find the horizontal asymptote, and then take limits as x approaches the vertical asymptote and the end behaviours.
Well, we know there will be a horizontal asymptote at y = 0, because as x approaches infinite and negative infinite, the graph will shrink down closer and closer to 0, but never touch it. We call this a horizontal asymptote.
So we know that there is a restriction on the y-axis.
Now, since we know the end behaviours, let's find the asymptotic behaviours.
As x approaches the asymptote of 7⁻, then y would be diverging out to negative infinite.
As x approaches the asymptote at 7⁺, then y would be diverging out to negative infinite.
So, our range would be:
Well when it comes to absolute value remember that whatever number is inside the two straight lines will always come out as a positive.
a) [54] would still be 54
b)-[-7 3/5] so first you get the absolute value which comes out to 7 3/5 but because there is a negative sign out side of the two parallel lines, the answer would be -7 3/5
c)[3]-[-1] the absolute value of 3 is 3 and the absolute value of -1 is 1. So the expression would be 3-1 which comes out to 2
d)[2.2-5.13] 2.2-5.13 would equal -2.93 but since it is in the absolute value, the answer would come out as 2.93
Hope this helps!
Answer:
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Step-by-step explanation:
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