Answer:
Im not really sure but take c & d out cuz they are wrong so it would just b and a but Id say it is A:)
Answer:
Multiproperty
Step-by-step explanation:
To solve this problem, we use different properties to arrive at our answer.
Given expression;
4(x + 3) = 20;
First we use the distributive property to expand;
4x + 12 = 20
Now use subtraction property by adding (-12) to both sides;
4x + 12 + (-12) = 20 + (-12)
4x = 8
you can now divide by 4,
x = 2
Answer:
x>2
Step-by-step explanation:
1) 6x+3 > 15
2) 6x > 15-3
3) 6x > 12
4) x > 12÷6
5) x > 2
Answer:
Step-by-step explanation:
a+b+c=0, a+b=-c,a+c=-b, b+c=-a
(a+b+c)^3=(a+b+c)^2*(a+b+c)=(a^2+b^2+c^2+2ab+2ac+2bc)*(a+b+c)=
a^3+ab^2+ac^2+2a^2b+2a^2c+2abc+a^2b+b^3+bc^2+2ab^2+2abc+2b^2c+a^2c+b^2c+c^3+2abc+2ac^2+2bc^2=a^3+b^3+c^3+3a^2b+3a^2c+3ac^2+3ab^2+3bc^2+3b^2c+6abc=
a^3+b^3+c^3+3a^2*(b+c)+3c^2(a+b)+3b^2(a+c)+6abc=
a^3+b^3+c^3+3a^2*(-a)+3c^2*(-c)+3b^2*(-b)+6abc=
a^3+b^3+c^3-3a^3-3c^3-3b^3+6abc=
6abc-2a^3-2b^3-2c^3=2(3abc-a^3-b^3-c^3)=
2*[3abc-(a^3+b^3+c^3)]=0
so 3abc-(a^3+b^3+c^3)=0
so a^3+b^3+c^3=3abc
