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lubasha [3.4K]
2 years ago
7

How many molecules of atp are produced as a result of glycolysis

Chemistry
2 answers:
Whitepunk [10]2 years ago
8 0

Answer:

2 ATP molecules are produced

abruzzese [7]2 years ago
5 0

Answer:

2 ATP molecules of ATP are produced

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Use the equation: 2 kclo3 2 kcl + 3 o2 to write the mole ratio needed to calculate: (a) moles of kcl produced from 3.5 moles of
poizon [28]

Answer:-

(a) 3.5

(b) 3

Explanation:-

2KClO3 --> 2KCl + 3 O2

From the equation we see that 2 moles of KClO3 gives 2 moles of KCl.

So 3.5 moles of KClO3 will give 3 moles of KCl.

Again

3 moles of O2 are produced with 2 moles of KCl.

If 4.5 moles of O2 produced then

moles of KCl = 4.5 x 2/3

=3

3 0
3 years ago
Which statement best describes the compressibility of a gas?
atroni [7]

Hey there!


The answer to this question would most likely be the 3rd choice, (option C)


Increasing the pressure on a gas decreases the volume


Good luck on your assignment and enjoy your day!


~LoveYourselfFirst:)

7 0
3 years ago
Which of the following mixtures may be act as a buffer solution?
lions [1.4K]

Answer:

B) HF, NaF

Explanation:

  • A buffer solution is made up of a weak acid and its conjugate base.
  • In this case, HF is a weak acid and NaF is the conjugate base, therefore the mixture of HF,  and NaF would make a perfect buffer solution.
  • The buffer would have the weak acid HF and its conjugate base, F- which comes from the soluble salt NaF.
4 0
3 years ago
One of the waste products produced by kidneys is creatinine. A healthy range ofcreatinine in human blood is between 0.50 mg/dL a
Anna35 [415]

The normal range of creatinine in human blood is between 0.50 mg/dL and 1.1 mg/dL. The patient's blood has a concentration of 0.0082 g/L. Let's convert that value into mg/dL.

We kwnot that there are 1000 mg in 1 g. And there are 10 dL in 1 L. We have to use those conversions.

1000 mg = 1 g 10 dL = 1 L

0.0082 g/L = 0.0082 g/L * 1000 mg/g = 8.2 mg/L * 1 L/ (10 dL) = 0.82 mg/dL

0.0082 g/L = 0.82 mg/dL

0.50 mg/dL < 0.82 mg/dL < 1.1 mg/dL

Answer: The concentration of creatinine = 0.82 mg/dL. It is in the normal range.

8 0
1 year ago
A 1.28-kg sample of water at 10.0 °C is in a calorimeter. You drop a piece of steel with a mass of 0.385 kg at 215 °C into it. A
Kryger [21]

Answer:

T_{2}=16,97^{\circ}C

Explanation:

The specific heats of water and steel are  

Cp_{w}=4.186 \frac{KJ}{Kg^{\circ}C}

Cp_{s}=0.49 \frac{KJ}{Kg^{\circ}C}

Assuming that the water and steel are into an <em>adiabatic calorimeter</em> (there's no heat transferred to the enviroment), the temperature of both is identical when the system gets to the equilibrium T_{2}_{w}= T_{2}_{s}  

An energy balance can be written as

m_{w}\times Cp_{w}\times (T_{2}- T_{1})_{w}= -m_{s}\times Cp_{s}\times (T_{2}- T_{1})_{s}  

Replacing

1.28Kg\times 4.186\frac{KJ}{Kg^{\circ}C}\times (T_{2}-10^{\circ}C)= -0.385Kg\times 0.49 \frac{KJ}{Kg^{\circ}C} \times (T_{2}-215^{\circ}C)

Then, the temperature T_{2}=16,97^{\circ}C

8 0
3 years ago
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