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SVETLANKA909090 [29]
3 years ago
8

What is s phisical change

Chemistry
2 answers:
cestrela7 [59]3 years ago
3 0
Physical change is where u change physically or on the "outside" hope this helps, have a great day!
Mama L [17]3 years ago
3 0

*scrolls through phone in confuzion* .-.

*the whole time me wifi disconnected* - windy outside..

-sigh impaitently ......


soo basically a "physical change is a change.. and i guess it can affect; *it affects* chemical substances...."

i quoted :)

example: boiling water


- hope this helps you and have a wonderful day/evening.

sorry if this joke was annoying or corny, just wanted to add nonsense humor to make someone sth... or find this relatable.. ://


*gives cookie*


-Wolfs c:

*remember to smile and say oof*

-and ofc eat cookie

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Which property of water causes water drops to bead on a freshly waxed car?
astraxan [27]

Answer:

Cohesive forces are greater than adhesive forces  

Step-by-step explanation:

The attractive forces between water molecules and the wax on a freshly-waxed car (adhesive forces) are quite weak.

However, there are strong attractive forces (cohesive forces) between water molecules.

The water molecules are only weakly attracted to the wax, so the cohesive forces pull the water molecules together to form beads .

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A woman is trying to make sweet tea, but she just can’t seem to get it sweet enough. Which method could help her dissolve more s
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3 years ago
Read 2 more answers
A bomb calorimeter has a heat capacity of 675 J/°C and contains 925 g of water. If the combustion of 0.500 mole of a hydrocarbon
ikadub [295]

<u>Answer:</u> The enthalpy of the reaction is 269.4 kJ/mol

<u>Explanation:</u>

To calculate the heat absorbed by the calorimeter, we use the equation:

q_1=c\Delta T

where,

q = heat absorbed

c = heat capacity of calorimeter = 675 J/°C

\Delta T = change in temperature = T_2-T_1=(53.88-24.26)^oC=29.62^oC

Putting values in above equation, we get:

q_1=675J/^oC\times 29.62^oC=19993.5J

To calculate the heat absorbed by water, we use the equation:

q_2=mc\Delta T

where,

q = heat absorbed

m = mass of water = 925 g

c = heat capacity of water = 4.186 J/g°C

\Delta T = change in temperature = T_2-T_1=(53.88-24.26)^oC=29.62^oC

Putting values in above equation, we get:

q_2=925g\times 4.186J/g^oC\times 29.62^oC=114690.12J

Total heat absorbed = q_1+q_2

Total heat absorbed = [19993.5+114690.12]J=134683.62J=134.7kJ

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat absorbed = 134.7 kJ

n = number of moles of hydrocarbon = 0.500 moles

\Delta H_{rxn} = enthalpy change of the reaction

Putting values in above equation, we get:

\Delta H_{rxn}=\frac{134.7kJ}{0.500mol}=269.4kJ/mol

Hence, the enthalpy of the reaction is 269.4 kJ/mol

6 0
3 years ago
Read 2 more answers
Natation TT mean to genetics
neonofarm [45]
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Hope this helps!
5 0
4 years ago
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