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Tanya [424]
2 years ago
7

Which of the following genotypes would result in a red phenotype?

Chemistry
1 answer:
OleMash [197]2 years ago
6 0
I would say 1 I think
You might be interested in
How many atoms are in 3.50 moles of calcium (ca)?
Paraphin [41]
It would be 70 because there are 20 atoms in one calcium molecule and that times 3.50 it is 70.
6 0
3 years ago
when chlorine is added to acetylene tetrachloroethane is formed How many grams of tetrachloroethane are ade if 15 liters of chlo
rodikova [14]

35.5 g of tetrachloroethane is added if 15 grams of chlorine is used with excess C_2H_2.

<h3>What is a balanced chemical equation?</h3>

A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge is  the same for both the reactants and the products.

Balanced chemical equation:

2Cl_2 (g) + C_2H_2 (g) → C_2H_2Cl_4(l)

In your case, 2 moles of chlorine gas are needed to produce 1 mole of tetrachloroethane, which implies that there's a 2:1 mole ratio between the two.

Calculating the mass of tetrachloroethane.

mC_2H_2Cl_4(l) = 15 g Cl_2 (g) X \frac{2 mol \;of \;Cl_2}{70 g \;Cl_2} X \frac{1 mol \;of \;C_2H_2Cl_4(l)}{2 mol \;Cl_2} X \frac{167.8 g \;C_2H_2Cl_4(l))}{1 mol \;C_2H_2Cl_4}

C_2H_2Cl_4(l) = 17.75 g

C_2H_2Cl_4(l) = 35.5 g

Hence, 35.5 g of tetrachloroethane is added if 15 gram of chlorine is used with excess C_2H_2

Learn more about balanced chemical equations here:

brainly.com/question/14998216

#SPJ1

8 0
2 years ago
Who had a good thanksgiving :D!!!
photoshop1234 [79]
Eh I guess it was okay what about you
5 0
3 years ago
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What kind of magnet is an electromagnet?
Inessa05 [86]
B. Temporary hope this helped :)
5 0
2 years ago
The enthalpy of vaporization of water at 373 K and 1 bar is 40.7 kJ/mol and the molar heat capacities are 75.3 J/(mol K) for liq
Soloha48 [4]

Answer:

The enthalpy of vaporization of water at 273 K and 1 bar = 44.9 KJ/mol

Explanation:

Enthalpy of vaporization of water at 273 K, ΔHvap(T₂) is given as;

ΔHvap(T₂) = ΔHvap(T₁) + ΔCp * (T₂ - T₁)

where ΔCp = molar heat capacity of gas - molar heat capacity of liquid

Therefore, ΔCp = (33.6 - 75.3) = -41.70 J/(mol K) = 0.0417 kJ/(molK)  

substituting  ΔCp = 0.0417 kJ/(mol K)  in the initial formula

;

ΔHvap(T) = ΔHvap(T1) + ΔCp * (T₂ - T₁)

ΔHvap(T₂)= 40.7 kJ/mol + {-0.0417 kJ/(mol K) * (272 - 373 K)}

ΔHvap(T₂) = 44.9 kJ/mol

Therefore,  enthalpy of vaporization of water at 273 K and 1 bar = 44.9kJ/mol

6 0
3 years ago
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