2 years ago

Please answer correctly as soon as possible!! I will give you brainliest

Mathematics

2 answers:

maw [93]2 years ago

7 0

Answers: y=-3 and x=7

STatiana [176]2 years ago

5 0

Answer: bAKAKAKAKAKAKAKAK ✔

Step-by-step explanation:

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A chili recipe calls for 2 pounds of ground pork and 3.5 pounds of ground beef. The cost of ground beef per pound is $0.20 less

dmitriy555 [2]

Answer: $\$1.75\ \text{per pound}$

Step-by-step explanation:

Given

The recipe calls for 2 Pounds of ground pork and 3.5 pounds of ground beef

Suppose x is the cost of ground pork

So, the cost of ground beef is $2x-0.2$

The total cost of meat is $\$15.05$

The total cost can also be written as

$\Rightarrow 2\times x+3.5\times (2x-0.2)=15.05\\\Rightarrow 2x+7x-0.7=15.05\\\Rightarrow 9x=15.75\\\Rightarrow x=\frac{15.75}{9}=\$1.75\ \text{per pound}$

So, the cost of ground pork is $\$1.75\ \text{per pound}$

5 0

3 years ago

marcus won 80% of the games of poker he played yesterday. If he won 4 games, how many games did he play

zlopas [31]

Games*80% = 4

g*.8 = 4

g = 4/.8

games = 5

5 games played

8 0

3 years ago

Read 2 more answers

a train takes 3hours less for a journey of 360 km if it's speed is increased by 10km/hr from it's usual speed.find usual speed o

tekilochka [14]

Answer:

30 km/h

Step-by-step explanation:

usual speed= x km/h

increased speed= x +10 km/h

distance= 360 km

time difference= 3 h

360/x= 360/(x+10) +3
360/x= (360+ 3x+30)/(x+10)
360(x+10)= x(390+3x)
360x+3600= 390x+ 3x²
3x² + 30 x -3600=0
x²+10x-1200=0
x=30 km/h

6 0

3 years ago

Dan paid $34.30 for a sweater. The price included a 40% markup. Find the cost of the sweater before the markup was added.

Nikolay [14]

140% = $34.30
1$ = 0.245
100% = 0.245 x 100 =$24.50

The cost of the sweater os $24.50

6 0

3 years ago

Find the limit, picture provided

Alex787 [66]

Answer:

Step-by-step explanation:

You are given that

$\lim_{x \to 4} f(x)=5;$
$\lim_{x \to 4} g(x)=0;$
$\lim_{x \to 4} h(x)=-2.$

Use the rule

$\lim_{x\to x_0}(f(x)+g(x))=\lim_{x\to x_0} f(x)+\lim_{x \to x_0} g(x).$

In your case,

$\lim_{x\to4}(f+g)(x)=\lim_{x\to4} (f(x)+g(x))= \lim_{x\to4} f(x)+ \lim_{x\to 4} g(x)=5+0=5.$

5 0

3 years ago