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skad [1K]
2 years ago
7

For what values of x is the absolute value of x less than or equal to 1.5? (Hint: Substitute numbers into the inequality |x| ≤ 1

.5 and see which numbers make the inequality true.) Complete the conjecture about when the absolute value of x is less than or equal to a given positive number k.
The absolute value of x is less than or equal to 1.5 when
(select)
. The absolute value of x is less than or equal to k when
(select)
.
Mathematics
1 answer:
o-na [289]2 years ago
8 0

Answer:

|x|<1.5

if x=0

0<1.5 is true

if x=1.5

1.5<1.5

true

if x=-1.5

|-1.5|<1.5

anything greater than 1.5 or less than -1.5 doesn't work

the way to solve is

assume that the inside is negative so if you had

|x|=a then to solve

x=a

x=-a

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Mary read a book that had 4200 pages last summer. If it took her 35 days to finish the book. How many pages did she read per day
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Do 4200/35............
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3 years ago
Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answ
enot [183]

2x - 3y = - 13

the equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

First obtain the equation in slope-intercept form

y = mx + c ( m is the slope and c the y-intercept )

calculate m using the gradient formula

m = ( y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (1, 5 ) and (x₂, y₂ ) = (- 2, 3 )

m = \frac{3-5}{-2-1} = \frac{-2}{-3}= \frac{2}{3}

y = \frac{2}{3} x + c ← partial equation

to find c substitute either of the 2 points into the partial equation

using (1, 5 ), then

5 = \frac{2}{3} + c ⇒ c = \frac{13}{3}

rearrange the equation into standard form

multiply through by 3

3y = 2x + 13 ( subtract 3y and 13 from both sides )

2x - 3y = - 13 ← in standard form


3 0
3 years ago
Read 2 more answers
Find a and b so that f(x) = x^3 + ax^2 + b will have a critical point at (2,3).
Digiron [165]

Using the critical point concept, it is found that a = -3 and b = 7.

<h3>What are the critical points of a function?</h3>
  • The critical points of a function are the values of x for which:

f^{\prime}(x) = 0

In this problem, the function is:

f(x) = x^3 + ax^2 + b

Hence, the derivative is:

f^{\prime}(x) = 3x^2 + 2ax

Then:

f^{\prime}(x) = 0

3x^2 + 2ax = 0

x(3x + 2a) = 0

x = 0

3x + 2a = 0

3x = -2a

x = -\frac{2a}{3}

Since the critical point is at x = 2, we have that:

-\frac{2a}{3} = 2

-2a = 6

2a = -6

a = -3

Then:

f(x) = x^3 - 3x^2 + b

Critical point at (2,3) means that when x = 2, y = 3, then:

3 = 2^3 - 3(2)^2 + b

8 - 12 + b = 3

b = 7

You can learn more about the critical point concept at brainly.com/question/2256078

4 0
2 years ago
I need help i need the statement and reason
Marina86 [1]
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6 0
3 years ago
What is the area of a square with a 80 ft. Perimeter
slega [8]

Answer:

400 sq. ft.

Step-by-step explanation:

We gotta find the length of a side:

First, we divide 80 by 4, because the perimeter of a square is (4 x side):

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Second, we doing the normal area of a square equation:

20^{2} = 400 square ft.

Which leads to out answer of 400 sq. ft.

5 0
3 years ago
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