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satela [25.4K]
3 years ago
14

A pharmaceutical company prefers experimental studies to conducting surveys or observational studies. what is most likely the re

ason for this preference?
Mathematics
2 answers:
never [62]3 years ago
8 0
Pharmaceutical companies prefers experimental studies to conducting surveys and observational studies because companies can manipulate or suggest methods easily to have good outcomes and they are able to directly observe the results. Experimental studies is a type of study in which a procedure and method is intentionally introduced.
tekilochka [14]3 years ago
3 0

Answer:

A.

Observational studies and surveys usually do not provide results that are as accurate as experimental results.


Step-by-step explanation:


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The probability that a randomly selected car with no 4-wheel drive has third-row seats is given by: Option B: 0.4

<h3>How to calculate the probability of an event?</h3>

Suppose that there are finite elementary events in the sample space of the considered experiment, and all are equally likely.

Then, suppose we want to find the probability of an event E.

Then, its probability is given as

P(E) = \dfrac{\text{Number of favorable cases}}{\text{Number of total cases}} = \dfrac{n(E)}{n(S)}

where favorable cases are those elementary events who belong to E, and total cases are the size of the sample space.

<h3>What is chain rule in probability?</h3>

For two events A and B, by chain rule, we have:

P(A \cap B) = P(B)P(A|B) = P(A)P(B|A)

where P(A|B) is probability of occurrence of A given that B already occurred.

For this case, the table given is:

Entries                          4-wheel drive        No 4-wheel drive        Total

Third Row Seats                  18                                12                        30

No Third Row Seats             7                                28                        35

Total                                     25                               40                        65

Let we take

A = event that a randomly selected car has no-4 wheel drive

B = event that a randomly selected car has third row seats

The total ways a car can be selected = 65 = n(S)

Total ways A can happen = n(A) = 40 (from the table).

Similarly, n(B) = 30

P(A) = n(A)/n(S) = 40/65

P(B) = n(B)/n(S) = 30/65

P(A∩B) = n(A∩B)/n(S) = 12/65

As by chain rule, we have:

P(A∩B) = P(A)P(B|A) = P(B)P(A|B)

We need P( A randomly selected car has three seats given that the selected car is with no 4-wheel drive)

which is symbolically P( B | A)

Thus, we use: P(A∩B) = P(A)P(B|A)

or

12/65 = (30/65)(P(B|A))\\\dfrac{12/65}{30/65} = P(B|A)\\\\P(B|A) = \dfrac{12}{30} = \dfrac{2}{5} = 0.4

Thus, the probability that a randomly selected car with no 4-wheel drive has third-row seats is given by: Option B: 0.4

Learn more about probability here:

brainly.com/question/1210781

3 0
2 years ago
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