X*y=72
x = 5y-2
x=72/y
72/y=5y-2
72=5y^2-2y
5y^2 -2y - 72 = 0
(5y+18)(y-4)=0
y = -18/5 discard
or y = 4
4x=72
x=18
(18,4)
If the limit of f(x) as x approaches 8 is 3, can you conclude anything about f(8)? The answer is No. We cannot. See the explanation below.
<h3>What is the justification for the above position?</h3>
Again, 'No,' is the response to this question. The justification for this is that the value of a function does not depend on the function's limit at a given moment.
This is particularly clear when we consider a question with a gap. A rational function with a hole is an excellent example that will help you answer this question.
The limit of a function at a position where there is a hole in the function will exist, but the value of the function will not.
<h3>What is limit in Math?</h3>
A limit is the result that a function (or sequence) approaches when the input (or index) near some value in mathematics.
Limits are used to set continuity, derivatives, and integrals in calculus and mathematical analysis.
Learn more about limits:
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Answer:
agidls
Step-by-step explanation:
Answer:
x=3
Step-by-step explanation:
First would need to convert the radical into a number.
And since if you have a perfect square of a radical it goes outside the square root sign, you would take the 3 and square it to make 9 and then take the 2 inside the square root sign and multiply so you have the square root of 18|
Since we have 
as the Leg c we would need to square it, squaring a square root sign would just cause them to be cancelled out and you being left with 18, afterwards find the square of 3, which is 9
18-9=9
square root of 9 = 3
Answer:
2
Step-by-step explanation:
let the other leg be x
Using Pythagoras' identity
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² + 1² = 3²
x² + 1 = 9 ( subtract 1 from both sides )
x² = 8 ( take the square root of both sides )
x = 
= 
= 
× = 2 ← exact value
