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steposvetlana [31]
2 years ago
13

If ∠WXZ≅∠YXZ and WZ = 38, what is YZ?

Mathematics
1 answer:
Katyanochek1 [597]2 years ago
3 0
<h3>Answer:  38</h3>

=================================================

Explanation:

The square markers tell us that we have right angles (aka 90 degree angles) at angle XYZ and XWZ. They are congruent by definition.

Another pair of congruent angles is WXZ and YXZ which are the left-most angles of each triangle.

The sides XZ and XZ are congruent to each other (reflexive property)

Based on those three previous paragraphs, we can use the Angle Angle Side (AAS) congruence theorem to prove that the triangles are congruent.

Specifically we could write \triangle XYZ \cong \triangle XWZ. The order of the letters is important so we know which letters pair up (eg: Y and W pair up as the 90 degree angles).

--------------------------------------

In short, the triangles are identical copies of each other. The upper triangle reflects over the line XZ to get the lower triangle, and vice versa. This means the smaller corresponding pieces must also be the same.

In this case, WZ = YZ = 38

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In △ABD and △ACD, we have

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A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 420 gram setting. It is
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Answer:

t=\frac{424-420}{\frac{26}{\sqrt{61}}}=1.202    

p_v =2*P(t_{(60)}>1.202)=0.234  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the true mean is NOT different from  420. So the specification is satisfied.

Step-by-step explanation:

Data given and notation  

\bar X=424 represent the sample mean

s=26 represent the sample standard deviation

n=61 sample size  

\mu_o =420 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 420 or not, the system of hypothesis would be:  

Null hypothesis:\mu = 420  

Alternative hypothesis:\mu \neq 420  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{424-420}{\frac{26}{\sqrt{61}}}=1.202    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=61-1=60  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(60)}>1.202)=0.234  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the true mean is NOT different from  420. So the specification is satisfied.

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