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Inessa [10]
3 years ago
11

Why is hydrogen placed in group one of the periodic table?

Chemistry
1 answer:
Mice21 [21]3 years ago
6 0

Answer:

Hydrogen has only 1 valence electron in its outermost shell.

Explanation:

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Consider the balanced equation below.
Karo-lina-s [1.5K]

The correct option is (a) H₂S : SO₂ = 2 : 2 and O₂ : H₂O = 3 : 2

<h3>What is molar Ratio ?</h3>

Molar ratio also known as stoichiometry is the ratio in which the reactants and products are either formed or reacted in the given equation

the balanced equation is as follows ;

2H₂S + 3O₂ --> 2SO₂ + 2H₂O

molar ratio can be determined by the coefficients of the compounds in the balanced reaction.

coefficient is the number in front of the chemical compound

coefficients for the compounds in this reaction are as follows ;

  • H₂S - 2
  • O₂ - 3
  • SO₂ - 2
  • H₂O - 2

therefore, correct option is (a) H₂S:SO₂ = 2:2 and O₂:H₂O = 3:2

Learn more about molar ratio here ;

brainly.com/question/17920577

#SPJ1

4 0
2 years ago
Which statements describing chemical and nuclear reactions are true?
Arte-miy333 [17]

Answer:

What statements?

Explanation:

they both release harmful chemicals and can pollute the earth and destroy our ecosystems.

8 0
2 years ago
Is chemistry hard in grade 11<br>explain to me everything plsss thanks ​
damaskus [11]

Answer: yes it’s hard

Explanation:

8 0
3 years ago
Read 2 more answers
Sulfonation of benzene has the following mechanism: (1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3 [fast] (2) SO3 + C6H6 → H(C6H5+)SO3− [slow]
ziro4ka [17]

Question is incomplete, complete question is as follows :

Complete Question : .Sulfonation of benzene has the following mechanism:

(1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3

[fast]

(2) SO3 + C6H6 → H(C6H5+)SO3−

[slow]

(3) H(C6H5+)SO3− + HSO4− → C6H5SO3− + H2SO4

[fast]

(4) C6H5SO3− + H3O+ → C6H5SO3H + H2O

[fast]

write the overall rate law for the initial rate of the reaction as a fraction.

Rate=k(________/_________)

Answer:

The overall rate law for the initial reaction is = k_{overall} [H_{2}SO_{4}]^{2} [C_{6}H_{6}]

Explanation :

Frist of all, all the common terms are cancelled out and written the overall reaction.

As we know that the rate depednant step is the slowest step of the reaction, rate law is :

                        rate = k_{2} [SO_{3}][C_{6}H_{6}]

But the problem is that SO3 cannot be written in the overall rate law because it is an intermediate.

Rate law for synthesis of S03 is as follows :

                       rate = k_{1}[H_{2}SO_{4}]^{2}

Hence when we substitute equation 2 in equation one,

                   Rate comes out to be =  k_{overall} [H_{2}SO_{4}]^{2} [C_{6}H_{6}]

6 0
3 years ago
a gas that exerts a pressure of 215 torr in a container with a volume of 51.0 mL will exert a pressure of ? torr when transferre
zhannawk [14.2K]
To calculate the new pressure, we can use Boyle’s law to relate these two scenarios (Boyle’s law is used because the temperature is assumed to remain constant). Boyle’s law is:

P1V1 = P2V2,

Where “P” is pressure and “V” is volume. The pressure and volume of the first scenario is 215 torr and 51 mL, respectively, and the second scenario has a volume of 18.5 L (18,500 mL) and the unknown pressure - let’s call that “x”. Plugging these into the equation:

(215 torr)(51 mL) =(“x” torr)(18,500 mL)
x = 0.593 torr

The final pressure exerted by the gas would be 0.593 torr.

Hope this helps!
3 0
3 years ago
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