I would say vapor pressure, but I could be wrong. Good luck ^^
CO2 is a compound, hope this is okay
Answer:
The empirical formula is C3H3O
Explanation:
Step 1: Data given
Suppose the mass of the molecule = 100 grams
The molecule contains:
65.5 % Carbon = 65.5 grams
5.5 % Hydrogen = 5.5 grams
29.0% Oxygen = 29.0 grams
Molar mass of C = 12 g/mol
Molar mass of H = 1.01 g/mol
Molar mass of O = 16 g/mol
Step 2: Calculate moles
Moles = mass / molar mass
Moles C = 65.5 grams / 12 g/mol = 5.46 moles
Moles H = 5.5 / 1.01 g/mol = 5.45 moles
Moles O = 29.0 grams / 16 g/mol = 1.8125 moles
Step 3: Calculate mol ratio
We divide by the smallest amount of moles
C: 5.46 / 1.8125 = 3
H = 5.45 / 1.8125 = 3
O = 1.8125/1.8125 = 1
The empirical formula is C3H3O
Answer:
0 to n − 1
Explanation:
The angular or orbital quantum number, gives a description of the particular subshell or orbital where the electron is found and gives the magnitude of its orbital angular momentum.
The values of the angular momentum quantum number (ℓ) takes on integer values that ranges from 0 to n − 1