Answer:
![p[H+] = 10.042](https://tex.z-dn.net/?f=p%5BH%2B%5D%20%3D%2010.042)
Explanation:
As we know that
......eq (1)
we will calculate the pH of OH- and then we will calculate the pH of H+
So p[OH-] ![= - log [1.10 * 10^{-4}]](https://tex.z-dn.net/?f=%3D%20-%20log%20%5B1.10%20%2A%2010%5E%7B-4%7D%5D)
Solving the right side of the equation, we get
p[OH-]
![= - [-3.958]\\= 3.958](https://tex.z-dn.net/?f=%3D%20-%20%5B-3.958%5D%5C%5C%3D%203.958)
Now we know that
Substituting the value of pOH in the above equation, we get -
![14.0 = p[H+] + 3.958\\p[H+] = 14 - 3.958\\p[H+] = 10.042](https://tex.z-dn.net/?f=14.0%20%3D%20p%5BH%2B%5D%20%2B%203.958%5C%5Cp%5BH%2B%5D%20%3D%2014%20-%203.958%5C%5Cp%5BH%2B%5D%20%3D%2010.042)
Answer:
50.3mL of mercury are in 1.50lb
Explanation:
Punds are an unit of mass. To convert mass to volume we must use density (13.546g/mL). Now, As you can see, density is in grams but the mass of mercury is in pounds. That means we need first, to convert pounds to grams to use density and obtain volume of mercury.
<em>Mass mercury in grams:</em>
1.50lb * (1kg / 2.20lb) = 0.682kg = 682g of mercury.
<em>Volume of mercury:</em>
682g Mercury * (1mL / 13.546g) =
<h3>50.3mL of mercury are in 1.50lb</h3>
Answer:
7430.5 Joules (7.4*10^4 Joules)
Explanation:
Q=mc∆T
where Q is energy in Joules.
Now m=250 g
c= 0.386 J/g°C
∆T = 99 - 22 = 77 °C
plugging the values in gives
Q=250*0.386*77=7430.5 Joules
(7.4*10^4 Joules, if 2 significant figures)
The relative humidity shows us saturation of water in air. Since it is 58% and not 100% we have to scale density that we were given when humidity is 100%.
At 100% humidity, density is 20grams/cubic meter
at 58% it will be:
0.58 * 20 = 11.6 g/m^3
Since the question is to find density, the answer cannot be in %.
Answer is 11.6 g/m^3
