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igomit [66]
2 years ago
10

8.3cm x 12.5cm(1 decimal place)

Mathematics
1 answer:
Diano4ka-milaya [45]2 years ago
3 0
I think the answer is 103.75 cm
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never [62]
$54.80 is the correct answer
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3 years ago
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Which set of values could be the side lengths of a 30-60-90 triangle?
jeyben [28]
If we say that side "a" is the shortest (adjacent), side "b" is the second shortest (opposite), and side "c" is the longest (hypotenuse): then angle A would be 30°,  angle B would be 60°, and angle C would be 90°

tan B = b/a
 or
a tan B = b

they have 4 as the smallest value in all four options, so we know that a=4

4 tan 60° = b
tan 60° = √3
so, 4 tan 60° = 4√3
b=4√3

that leaves two options left, so now we find "c":

c^2 = (a^2) + (b^2)
OR
c= \sqrt{a^{2} + b^{2}}

c= \sqrt{4^{2}+(4\sqrt{3})^{2}}

c= \sqrt{16+48} \\ c=\sqrt{64} \\ c=8

so a=4, b=4√3, and c=8

Making your answer B
3 0
3 years ago
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An insurance company selected a random sample of 500 clients under 18 years of age and found that 180 of them had had an acciden
Butoxors [25]

Answer:

a) The pooled proportion is p=0.3.

b) P-value = 0.000078

c) Lower bound = 0.0556

d) Upper bound = 0.1644

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the accident proportions differ between the two age groups .

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0

The significance level is 0.05.

The sample 1, of size n1=500 has a proportion of p1=0.36.

p_1=X_1/n_1=180/500=0.36

The sample 2, of size n2=600 has a proportion of p2=0.25.

p_1=X_1/n_1=150/600=0.25.

The difference between proportions is (p1-p2)=0.11.

p_d=p_1-p_2=0.36-0.25=0.11

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{180+150}{500+600}=\dfrac{330}{1100}=0.3

The standard error for the difference between proportions can now be calculated as:

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.3*0.7}{500}+\dfrac{0.3*0.7}{600}}\\\\\\s_{p1-p2}=\sqrt{0.00042+0.00035}=\sqrt{0.00077}=0.0277

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.11-0}{0.0277}=\dfrac{0.11}{0.0277}=3.964

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=2\cdot P(t>3.964)=0.000078

As the P-value (0.000078) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is  enough evidence to support the claim that the accident proportions differ between the two age groups.

If we want to calculate the bounds of a 95% confidence interval, we start by calculating the margin of error.

For a 95% CI, the critical value for z is z=1.96.

Then, the margin of error is:

MOE=z \cdot s_{p1-p2}=1.96\cdot 0.0277=0.0544

Then, the lower and upper bounds of the confidence interval are:

LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.11-0.0544=0.05561\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.11+0.0544=0.16439

The  95% confidence interval for the population mean is (0.0556, 0.1644).

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Becky is counting backward from 18.5. Identify the pattern she is using and complete the sequence of numbers.
Stells [14]
Answer: The pattern is -1.25 and the full sequence of numbers are 18.5, 17.25, 16, 14.75, and 13.5.
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Please help asap<br><br> rewrite c + 1/4c as a single term with a fractional coefficient.
My name is Ann [436]
C is same thing as 1c

1c + 1/4c

(In simple words: Adding a whole to 1/4.)
1 + 1/4 = 1 1/4 or 5/4
same thing when having c:
1c + 1/4c = 1 1/4c or 5/4 c

Answer: 1 1/4c or 5/4c
3 0
4 years ago
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