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zhannawk [14.2K]
2 years ago
14

Guy Please Help Me, I Will Give U An Award If U Give Me The Right Answer And Not Any Link, Just The Answer.

Mathematics
2 answers:
Gwar [14]2 years ago
7 0

Answer:

I think it shows a function

Step-by-step explanation:

inputs are being changed by 10's

draw it in a table 2*10=20 2*20=40

3*10=30

4*10=40

disa [49]2 years ago
3 0

Answer:

It is not a function.

Step-by-step explanation:

This is what we call a mapping;

Functions do not give multiple output values for a given input value;

As we can see, the input 2 produces an output of 20 and 40, therefore we can tell this is not a function.

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A 30cm ruler sometimes measures inches on the other side.
Alisiya [41]

1inch = 2.5cm

∆ 30cm

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  1. so 30cm=12inch
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2 years ago
A recent survey of 50 executives who were laid off during a recent recession revealed it took a mean of 26 weeks for them to fin
drek231 [11]

Answer:

The pvalue of 0.0113 < 0.05 means that there is sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance

Step-by-step explanation:

The null hypothesis is:

H_{0} = 28

The alternate hypotesis is:

H_{1} < 28

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

A recent survey of 50 executives who were laid off during a recent recession revealed it took a mean of 26 weeks for them to find another position.

This means that n = 50, X = 26

Assume the population standard deviation is 6.2 weeks.

This means that \sigma = 6.2

Does the data provide sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance

We have to find the pvalue of Z, looking at the z-table, when \mu = 28. It if is lower than 0.05, it provides evidence.

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{26 - 28}{\frac{6.2}{\sqrt{50}}}

z = -2.28

z = -2.28 has a pvalue of 0.0113 < 0.05.

The pvalue of 0.0113 < 0.05 means that there is sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance

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3 years ago
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agasfer [191]
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Luba_88 [7]

Answer x=6

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move the constant to the right hand side and change its sign

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