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Bas_tet [7]
3 years ago
12

a rectangle has a length of 8 feet and a width of 6 feet. if its length and width increase bye 50%, what is the new area of the

rectangle
Mathematics
1 answer:
Alik [6]3 years ago
7 0

Answer:

108ft squared

Step-by-step explanation:

Length increased by 50%: 12ft

Width increased by 50%: 9ft

12x9=108ft squared

I think this is right please confirm before using this answer. Please favorite if right.

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Find an explicit rule for the nth term of the sequence.The second and fifth terms of a geometric sequence are 18 and 144, respec
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Given:

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\begin{gathered} a_n\text{ = ar}^{n-1} \\ Where\text{ a is the first term} \\ r\text{ is the common ratio} \end{gathered}

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\begin{gathered} \text{ar}^{2-1}\text{ = 18} \\ ar\text{ = 18} \\  \\ ar^{5-1}=\text{ 144} \\ ar^4\text{ =144} \end{gathered}

Divide the expression for the fifth term by the expression for the second term:

\begin{gathered} \frac{ar^4}{ar}\text{ = }\frac{144}{18} \\ r^3\text{ = }\frac{144}{18} \\ r\text{ = 2} \end{gathered}

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