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3 years ago

Order 3, -2.5, 1 1/2, -2 2/3, 1.3 from least to greatest

Mathematics

1 answer:

enot [183]3 years ago

7 0

Answer:-2 2/3 < -2.5 < 1.3 < 1 1/2 < 3

Step-by-step explanation:

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True or False. All segments have a perpendicular bisector.

puteri [66]

<span>Without drawing a line on a piece of graph paper. If you know the endpoints of the line segment you can determine the equation of the line and the midpoint of the line. The slope of a perpendicular to a line is the negative reciprocal of the slope of the original line. You can then determine the equation of the perpendicular bisector using the point-slope method. Using a compass and straight edge, you can draw the line. set the compass at the endpoint and wide enough to extend beyond the midpoint. Scribe an arc. Without changing the compass use the other end and scribe another arc so that the two arcs intersect. Connect the two points where the arcs intersect and scribe a line through them. That is the perpendicular bisector.

i found this online ^ hope i helped ^-^</span>

8 0

3 years ago

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What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

Simplifying the terms, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}$

Multiplying, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}$

Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

7 0

3 years ago

8y-2=-18 what is the answer

enot [183]

The answer is: y=-2

4 0

3 years ago

2xsquare+12x+19<br> Find the minimum value of f (x)

Arturiano [62]

Converting to vertex form is one way of doing this
2x^2 + 12x + 19
= 2(x^2 + 6x) + 19
= 2 [ x + 3)^2 - 9] + 19
= 2(x + 3)^2 - 18 + 19
= 2(x + 3)^2 + 1

the minimum value is 1

5 0

3 years ago

PLS HELP WILL MARK BRAINLIEST TO BEST ANSWER

butalik [34]

I believe 504,000 seconds

6 0

3 years ago

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